小编Rid*_*lah的帖子

我真的好奇为什么会这样.我创建了两个对象.一个是另一个孩子.我在事件监听器ADDED_TO_STAGE中注册了两个.classB中的onAdded方法执行两次.

为什么会发生这种情况？如何防止这种行为？

thanx回答

public class ClassA extends Sprite 
{
        public function ClassA () 
        {
            this.addEventListener(Event.ADDED_TO_STAGE, onAdded);
        }

        private function onAdded(e:Event):void
        {
            trace("ON ADDED 1");
            var classB : ClassB = new ClassB();
            addChild(classB);
        }
}

public class ClassB extends Sprite 
{
        public function ClassB () 
        {
            this.addEventListener(Event.ADDED_TO_STAGE, onAdded);
        }

        private function onAdded(e:Event):void
        {
            trace("ON ADDED 2");
        }
}

OUTPUT:ON ADDED 1 ON ADDED 2 ON ADDED 2

我有与服务器通信的Flash游戏.如果出现问题,我想显示弹出窗口.有什么东西被按下确定按钮刷新游戏.

btnHolder.addEventListener(MouseEvent.CLICK, refreshPage);

private function refreshPage(e:MouseEvent):void
{
...
}

我怎样才能做到这一点 ？这甚至可能吗？或者我可以做的最多只是弹出文本"刷新浏览器".

我创建了哈希.比我在控制台上打印它.复制哈希值并将其放入代码进行比较.但它产生的不一样.

        String input = "Hello";
        String key = "Key";
        Byte[] hashKey = Encoding.UTF8.GetBytes(key);

        HMACSHA1 hmac = new HMACSHA1(hashKey);
        Byte[] computedHash = hmac.ComputeHash(Encoding.UTF8.GetBytes(input));
        String computedHashString = Encoding.UTF8.GetString(computedHash);
        Console.WriteLine("Hash value of your input: .{0}.", computedHashString);

        if ("?:????W?u$YLR;???T?j" == computedHashString)
        {
            Console.WriteLine("They are same!");
        }
        else
        {
            Console.WriteLine("They are NOT same!");
        }

        Console.ReadLine();

先感谢您