小编Dav*_*man的帖子

我想基本上创建API 21+ tintxml属性的"支持"版本.如何tint在代码中从drawable 获取属性(或自定义属性),而不View对每个图像使用自定义？

这是/res/drawable/brandable_icon_slider_featured.xml代码:

<?xml version="1.0" encoding="utf-8"?>
<bitmap xmlns:android="http://schemas.android.com/apk/res/android"
    xmlns:tintns="http://schemas.android.com/apk/res-auto"
    android:src="@drawable/brandable_icon_slider_featured_img"
    tintns:tintColor="@color/branded_menu" />

然后我创建了一个自定义Resources子类并在我的活动中使用它.

public class CustomResource extends Resources {
    ...

    @Override
    public XmlResourceParser getXml(int id) throws NotFoundException {
        XmlResourceParser parser = super.getXml(id);
        return parser;
    }

    @Override
    public Drawable getDrawableForDensity(int id, int density) throws NotFoundException {
        return replaceWithTintableBitmap(super.getDrawableForDensity(id, density));
    }

    @Override
    public Drawable getDrawableForDensity(int id, int density, Theme theme) {
        return replaceWithTintableBitmap(super.getDrawableForDensity(id, density, theme));
    }

    @Override
    public Drawable getDrawable(int id) throws NotFoundException …