嘿家伙我试图找到隐藏字符串的方法,但我发现的代码只适用于我的应用程序...有没有办法用"*"或" - "隐藏字符串中的字符,如果有的话是有人可以请解释
我试图隐藏我从文本文件中的列表中检索到的随机单词,但代码一直给我以下错误: Array Required, but java.lang.String found
import java.awt.*;
import java.awt.event.*;
import java.util.Arrays;
import javax.swing.*;
import java.io.*;
import java.util.ArrayList;
import java.util.Random;
import java.util.List;
public class Hangman extends JFrame
{
private static final char HIDECHAR = '_';
String imageName = null;
String Path = "D:\\Varsity College\\Prog212Assign1_10-013803\\images\\";
static int guesses =0;
private String original = readWord();
private String hidden;
int i = 0;
static JPanel panel;
static JPanel panel2;
static JPanel panel3;
static JPanel panel4;
public Hangman(){
JButton[] buttons = new JButton[26];
this.original …Run Code Online (Sandbox Code Playgroud) java ×2