我想使用maven-failsafe-plugin来运行一些集成测试.如果任何测试失败,我希望Maven失败构建而不是BUILD SUCCESS.
Tests run: 103, Failures: 1, Errors: 0, Skipped: 26
[INFO] BUILD SUCCESS*
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我怎样才能配置它,那个构建不成功的是什么?
我的故障安全插件配置为:
<plugin>
<groupId>org.apache.maven.plugins</groupId>
<artifactId>maven-failsafe-plugin</artifactId>
<version>${failsafe.version}</version>
<configuration>
<systemProperties>
<CI_INTEGRATION_OVERRIDE_PATH>${basedir}/..</CI_INTEGRATION_OVERRIDE_PATH>
</systemProperties>
<includes>
<include>**/integration/**/*.java</include>
</includes>
<excludes>
<exclude>**/integration/**/*TestSuite.java</exclude>
</excludes>
</configuration>
<executions>
<execution>
<id>integration-test</id>
<goals>
<goal>integration-test</goal>
<goal>verify</goal>
</goals>
</execution>
</executions>
</plugin>
Run Code Online (Sandbox Code Playgroud) 有人能告诉我如何在Oracle中删除一个程序,但它是否存在?
DROP PROCEDURE IF EXISTS XYZ;
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以上不起作用.
这是一个非常简单的spring + hibernate示例.我在这做错了什么?
DTO:
package com.xx.dto;
import java.util.Date;
import javax.persistence.*;
@Entity
@Table(name = "users")
public class UserData {
@Id
@GeneratedValue
@Column(name = "id")
private Integer id;
@Column(name = "user_firstname")
private String firstname;
@Column(name = "user_lastname")
private String lastname;
@Column(name = "user_sex")
private String sex;
@Column(name = "user_birthdate")
private Date birthDate;
@Column(name = "user_email")
private String email;
public Integer getId() {
return id;
}
public void setId(Integer id) {
this.id = id;
}
public String getFirstname() {
return firstname;
}
public …
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