我有一个使用AFNetworking处理JSON解析数据的问题.
这是我的代码:
AFHTTPRequestOperationManager *manager = [AFHTTPRequestOperationManager manager];
manager.responseSerializer = [AFHTTPResponseSerializer serializer];
NSDictionary *parameters = @{@"strEmail": _logInEmail.text, @"strPassword":_logInPassword.text};
[manager POST:@"http://carefid.com/api/user/login.php" parameters:parameters success:^
(AFHTTPRequestOperation *operation, id responseObject) {
//NSString *string = [[NSString alloc] initWithData:responseObject encoding:NSUTF8StringEncoding];
NSString *str = responseObject[@"error"];
NSLog(@"JSON: %@", str);
UIViewController *myController = [self.storyboard instantiateViewControllerWithIdentifier:@"rootController"];
[self presentViewController:myController animated:YES completion:nil];
} failure:^(AFHTTPRequestOperation *operation, NSError *error) {
NSLog(@"Error: %@", error);
}];
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当我试图记录该值时,我收到此错误:
2014-07-15 14:39:08.438 carefid[7858:60b] -[_NSInlineData objectForKeyedSubscript:]: unrecognized selector sent to instance 0x1094c67a0
2014-07-15 14:39:08.441 carefid[7858:60b] *** Terminating app due to uncaught …
Run Code Online (Sandbox Code Playgroud) 我有一个UIViewController
与UITableView
当的tableView是空的,我想展现另一种看法,所以我用这个
[self.tableView setHidden:YES];
NoKidsViewController *noKids = [self.storyboard instantiateViewControllerWithIdentifier:@"NoKidsView"];
[self.view addSubview:noKids.view];
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一切都很好,我能看到这个观点.但当我点击其中一个按钮时,我收到EXC_BAD_ACCESS EXC_I386_GPFLT
错误.
//NoKidsViewController
- (IBAction)addNewKid:(id)sender {
AddKid *addKidController = [self.storyboard instantiateViewControllerWithIdentifier:@"AddKid"];
[self.navigationController pushViewController:addKidController animated:YES];
}
- (IBAction)saleSpot:(id)sender {
SaleSpot *saleSpotController = [self.storyboard instantiateViewControllerWithIdentifier:@"AddKid"];
[self.navigationController pushViewController:saleSpotController animated:YES];
}
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我在网上搜索了3个多小时,试图找到没有成功的解决方案.什么可能导致错误?我该如何解决?