我用fabric.js创建简单的工具,我需要添加功能,用键盘移动对象.我被卡住.目前我登录到控制台键盘事件,所以我知道它的工作原理.但我不知道如何将这种功能添加到我的画布图像.并帮助？
$(function(){
var canvas = new fabric.Canvas('imageCanvas', {
backgroundColor: 'rgba(255, 255, 255, 0)'
});
var imageLoader = document.getElementById('imageLoader');
imageLoader.addEventListener('change', handleImage, false);
function handleImage(e) {
var reader = new FileReader();
reader.onload = function (event) {
var img = new Image();
img.onload = function () {
var imgInstance = new fabric.Image(img, {
})
canvas.add(imgInstance);
}
img.src = event.target.result;
}
reader.readAsDataURL(e.target.files[0]);
}
canvas.on('mouse:down', function(options) {
console.log(options.e.clientX, options.e.clientY);
});
var canvasWrapper = document.getElementById('canvasWrapper');
canvasWrapper.tabIndex = 1000;
canvasWrapper.addEventListener("keydown", doKeyDown, false);
function doKeyDown(e) {
document.onkeydown = …我在Mysql中有以下2个选择:
第一选:
(SELECT DISTINCT `Online_playerdatabase_v2`.`Player`,
Online_playerdatabase_v2.First_Deposit_Date As FirstDep,
TRUNCATE(Online_playerdatabase_v2.Balance,2) as Balance
FROM Online_playerdatabase_v2
WHERE `Online_playerdatabase_v2`.`Player`<>'Player'
ORDER BY `Online_playerdatabase_v2`.`Balance` DESC;
2d选择:
SELECT DISTINCT(Online_customer_activity_v2.Customers) as Player,
max(Online_customer_activity_v2.Date) as LastAction
FROM Online_customer_activity_v2
WHERE `Online_customer_activity_v2`.`Total_Bets`>0
Group by Online_customer_activity_v2.Customers
输出选择1
Player FirstDep Balance
Ray 2014-10-19 9100.00
Ramzi 2014-11-02 9.61
tareq 2014-11-06 805.00
STAN 2014-10-17 7.50
Bill 2014-03-25 68.40
karam 2014-11-16 676.50
Abdul 2014-11-13 650.00
Renaud 2014-03-12 507.00
John 2014-11-22 500.00
输出选择2
Player LastAction
John 2015-11-13
Bill 2014-12-14
Renaud 2015-03-14
Abdul 2015-11-16
Ray 2015-11-22
STAN 2015-10-29 …我正在研究以下代码,其中我想使用php if conditions多个非运算符的多个(示例如下).
但是当我执行跟随时php code,它总是返回true(括号中的平均内容总是执行)甚至条件为假.
我想问一下下面代码中的问题是什么,是否有使用多个的特定语法或规则!= operator in php conditions？我很惊讶地看到,如果我用替换下面的代码!= operator与== operator它工作正常.
if( $ext!="exe" || $ext!="html" || $ext!="htm" || $ext!="js" || $ext!="iso" || $ext!="zip" || $ext!="rar" )
{ // ececk extension
echo $ext."extension";
}
else{
echo "not match";
}
等待你的回复.抱歉我的英语不好