小编moz*_*ima的帖子

我应该使用哪一个来从Openid auth proccess索引用户."openid_identity"或"openid_claimed_id"？我使用Dope OpenId类并返回的数据是:

[openid_ns] => http://specs.openid.net/auth/2.0
[openid_mode] => id_res
[openid_return_to] => http://localhost/login/authenticate
[openid_claimed_id] => https://me.yahoo.com/a/wK7..MjM-#607
[openid_identity] => https://me.yahoo.com/a/wK7...MjM-
[openid_realm] => http://localhost/
[openid_assoc_handle] =>odm...j24yhwlT...2TOXQ9.sifIz3eLZoU.....jOoGM...9VPcMVavQkVgEQ--
[openid_response_nonce] => 2009-09-19T12:35:08Z95e...WtOYlQ--
[openid_signed] => assoc_handle,claimed_id,identity,mode,ns,op_endpoint,response_nonce,return_to,signed,ns.pape,pape.auth_level.ns.nist,pape.auth_level.nist,pape.auth_policies
[openid_op_endpoint] => https://open.login.yahooapis.com/openid/op/auth
[openid_ns_pape] => http://specs.openid.net/extensions/pape/1.0
[openid_pape_auth_level_ns_nist] => http://csrc.nist.gov/publications/nistpubs/800-63/SP800-63V1_0_2.pdf
[openid_pape_auth_level_nist] => 0
[openid_pape_auth_policies] => http://schemas.openid.net/pape/policies/2007/06/none
[openid_sig] => kO7......EitU=

谢谢

我需要用逗号和空格分割字符串,但忽略内部引号,单引号和括号

$str = "Questions, \"Quote\",'single quote','comma,inside' (inside parentheses) space #specialchar";

这样得到的数组就会有

[0]Questions
[1]Quote
[2]single quote
[3]comma,inside
[4]inside parentheses
[5]space
[6]#specialchar

我的正常表现是

$tags = preg_split("/[,\s]*[^\w\s]+[\s]*/", $str,0,PREG_SPLIT_NO_EMPTY);

但是这忽略了特殊的字符,stil将逗号分隔在引号内,结果数组为:

[0]Questions
[1]Quote
[2]single quote
[3]comma
[4]inside
[5]inside parentheses
[6]space
[7]specialchar

ps:这不是csv

非常感谢