我有以下代码:
object Test extends App {
import Macros._
val f = 1
Macros.get(f)
}
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import language.experimental.macros
import scala.reflect.macros.Context
object Macros {
def get(a: Int) = macro getImpl
def getImpl(c: Context)(a: c.Expr[Int]) = {
import c.universe._
println(showRaw(a))
}
}
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它返回:
Expr(Select(This(newTypeName("Test")), newTermName("f")))
如何从termName("f")一个1值中提取?有可能用宏吗?
我有下一堂课:
case class Foo(a: Option[Int], b: Option[String], c: Option[Double])
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正如您所看到的,所有字段都是可选的,我希望将此类转换为HList或Tuple,就像
val f1 = Foo(Some(1) , None, Some(3D))
val f2 = Foo(None, "foo")
val result1 = f1.to[Int::Double::HNil] // => 1::3D
val result2 = f2.to[String::HNil] // "foo"
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没有反思可能吗?
我使用shapeless进行case类转换,我有一个2个案例类:
import shapeless._
case class Foo(id: Int, name: String)
case class Bar(id: Int, name: String, price: Double)
val fooGen = Generic[Foo]
val barGen = Generic[Bar]
val foo = Foo(1, "foo")
val fooRepr = fooGen.to(foo)
val additional = fooRepr :+ 1.0
val bar = barGen.from(additional)
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这工作正常,但当我尝试将Bar转换为Foo时
fooGen.from(barGen.to(bar))
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我收到一个错误:
found : main.barGen.Repr
[error] (which expands to) shapeless.::[Int,shapeless.:: [String,shapeless.::[Double,shapeless.HNil]]]
[error] required: main.fooGen.Repr
[error] (which expands to) shapeless.::[Int,shapeless.::[String,shapeless.HNil]]
[error] println(fooGen.from(barGen.to(bar)))
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是否有可能将一个案例类转换为更多字段而不是另一个案例类?
我有两个主题:
// photos
{'id': 1, 'user_id': 1, 'url': 'url#1'},
{'id': 2, 'user_id': 2, 'url': 'url#2'},
{'id': 3, 'user_id': 2, 'url': 'url#3'}
// users
{'id': 1, 'name': 'user#1'},
{'id': 1, 'name': 'user#1'},
{'id': 1, 'name': 'user#1'}
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我按用户创建地图照片
KStream<Integer, Photo> photo_by_user = ...
photo_by_user.to("photo_by_user")
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然后,我尝试连接两个表:
KTable<Integer, User> users_table = builder.table("users");
KTable<Integer, Photo> photo_by_user_table = builder.table("photo_by_user");
KStream<Integer, Result> results = users_table.join(photo_by_user_table, (a, b) -> Result.from(a, b)).toStream();
results.to("results");
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结果就像
{'photo_id': 1, 'user': 1, 'url': 'url#1', 'name': 'user#1'}
{'photo_id': 2, 'user': 2, 'url': 'url#2', 'name': …Run Code Online (Sandbox Code Playgroud)