操作系统:Windows 10 Perl6:这是在MoarVM版本2018.04.1上构建的Rakudo Star版本2018.04.1,实现了Perl 6.c.
例:
perl6 C:\Users\quest\Desktop\example.pl
# sucess
perl6 "C:\Users\quest\Desktop\??\Perl 6\web-scraping\request.pl"
# Could not open C:\Users\quest\Desktop\????\Perl 6\web-scraping\request.pl. Failed to open file C:\Users\quest\Desktop\????\Perl 6\web-scraping\request.pl: No such file or directory
Python 3示例:
py "C:\Users\quest\Desktop\??\py\3\timetest.py"
# sucess
“ CATCH”是否应该在“ throw”之后严格调用？
范例1：
say 'Hello World!';
class E is Exception { method message() { "Just stop already!" } }
CATCH {
when E {
.resume;
}
}
E.new.throw;
错误：
找不到方法“接收器”：在/tmp/739536251/main.pl6第11行的块中没有方法缓存，也没有。^ find_method
范例2：
say 'Hello World!';
class E is Exception { method message() { "Just stop already!" } }
E.new.throw;
CATCH {
when E {
.resume;
}
}
没错
server-udp.pl
my $socket = IO::Socket::Async.bind-udp('localhost', 3333);
react {
whenever $socket.Supply -> $v {
if $v.chars > 0 {
$v.print;
}
}
}
client-udp.pl
my $socket = IO::Socket::Async.udp();
await $socket.print-to('localhost', 3333, "\nHello, Perl 6!");
客户端如何读取服务器响应？
也许这还没有实现？
例如在Perl 5中:
client.pl
...
my $data_send = "Test 1234567890";
$client_socket->send( $data_send )
or die "Client error while sending: $!\n";
# read operation
$client_socket->recv( my $data_rcv , 1024 )
or die "Client error while received: $!\n";
print "Received data: $data_rcv\n";
...
这是基于实现Perl 6.d的MoarVM版本2019.03构建的Rakudo Star版本2019.03.1。
Windows 10
例子：
1）错误：
shell 'mysqldump -uroot -ppassword asppmr > D:\b\29-09-2019 19-45-18\asppmr.sql';
mysqldump：[警告]在命令行界面上使用密码可能不安全。mysqldump：找不到表：“ 19-45-18 \ asppmr.sql” Proc.new（in => IO :: Pipe，out => IO :: Pipe，err => IO :: Pipe，exitcode => 6，信号=> 0，pid => 11928，命令=>（“ mysqldump -uroot -ppassword asppmr> D：\ b \ 29-09-2019 19-45-18 \ asppmr.sql”））
2）错误：
shell 'mysqldump -uroot -ppassword asppmr > "D:\b\29-09-2019 19-45-18\asppmr.sql"';
??????????????? ?????? ？?????? ??????，????? ?????? ??? ?????? ????。Proc.new（in => IO :: Pipe，out => IO :: Pipe，err => IO :: Pipe，exitcode => 1，信号=> 0，pid …
// define('DOCROOT', realpath(dirname(__DIR__)));
// good
const DOCROOT = realpath(dirname(__DIR__));
// PHP Parse error: syntax error, unexpected '(', expecting ',' or ';' in
为什么会出错？