小编Sri*_*ran的帖子

我在angularJS应用程序中有两个自定义指令.一个充当父母,另一个充当孩子.我试图访问子指令内的父范围.但我没有得到所需的输出.

<div ng-controller="CountryCtrl">
{{myName}}
    <div ng-controller="StateCtrl">
        <state nameofthestate="'Tamilnadu'">
            <city nameofthecity="'Chennai'"></city>
        </state>
    </div>
</div>

我的剧本看起来像

var app = angular.module("sampleApp",[]);
app.controller("CountryCtrl",function($scope){
    $scope.myName = "India";
});
app.controller("StateCtrl",function($scope){
});
app.directive("state",function(){return {
    restrict : 'E',
    transclude: true,
    scope : { myName  : '=nameofthestate'},
    template:"**   {{myName}} is inside {{$parent.myName}}<br/><ng-transclude></ng-transclude>"
}});
app.directive("city",function(){return {
    restrict : 'E',
    require:'^state',
    scope : { myName  : '=nameofthecity'},
    template:"****   {{myName}} is inside {{$parent.myName}} which is in {{$parent.$parent.myName }}<br/> "
}});

相应的JSFiddle可在https://jsbin.com/nozuri/edit?html,js,output中找到

我得到的输出是

India
** Tamilnadu is inside India
**** Chennai is …

我有一个 JSON 数据，我想按字段分组，然后按计数排序。

var data = [{"Name":"Ravi","Country":"India"},
            {"Name":"Alex","Country":"USA"},
            {"Name":"Stew","Country":"UK"},
            {"Name":"Mary","Country":"India"},
            {"Name":"Raju","Country":"India"},
            {"Name":"Bill","Country":"UK"},
            {"Name":"Elisa","Country":"UK"},
            {"Name":"Sharma","Country":"India"}];

我的 d3.js 查询如下

var countryCount = d3.nest()
                    .key(function(d) { return d.Country; })
                    .rollup(function(a){return a.length;})
                    .entries(data);
console.log(JSON.stringify(countryCount));

我的输出是

[{"key":"India","values":4},{"key":"USA","values":1},{"key":"UK","values":3}]

我想要的输出是（按汇总值排序）

[{"key":"India","values":4},{"key":"UK","values":3},{"key":"USA","values":1}]

我怎样才能做到这一点？我知道以下浏览器默认排序方法也提供了所需的输出。但只是想弄清楚 d3.js 是否提供任何内置方法来实现这一点。

console.log(JSON.stringify(countryCount.sort(function (a, b){
    if (a.values > b.values) {return -1;} 
    else if (a.values < b.values) { return 1;} 
    else  return 0;
})));