小编And*_*Geo的帖子

我正在做论文,我必须将源代码解析并标记为单个函数.对于每个函数,我想提取类型的名称,称为函数名称和类型转换.铿锵声是这种工作的正确工具吗？如果是,我该怎么做？

下面是一个简单的C函数.粗体是我想要的提取项目:

static char func1(unsigned int a, struct foo *b)
{
    int c = 0;
    struct bar *d;

    if (a == 0) {
        d = func2((int) a);
    } else {
        c = func3((struct bar *) b);
    }

    return c;
}

您好，我正在尝试实现AST Clang访问者，这是我的代码。

class ExampleVisitor : public RecursiveASTVisitor<ExampleVisitor> {
private:
    ASTContext *astContext; // used for getting additional AST info

public:
    virtual bool VisitVarDecl(VarDecl *var) 
    {
        numVariables++;
        string varName = var->getQualifiedNameAsString();
        string varType = var->getType().getAsString();
        cout << "Found variable declaration: " << varName << " of type " << varType << "\n";
        APIs << varType << ", ";
        return true;
    }

    virtual bool VisitFunctionDecl(FunctionDecl *func)
    {
        numFunctions++;
        string funcName = func->getNameInfo().getName().getAsString();
        string funcType = func->getResultType().getAsString();
        cout << "Found function declaration: " << …

我正在尝试确定ASTvisitor中的变量声明是否为数组，如果为数组，则要确定数组的维数。在下面可以找到我的代码。

bool VisitVarDecl(VarDecl *var)
    {
        if (astContext->getSourceManager().isInMainFile(var->getLocStart())) //checks if the node is in the main = input file.
        {
            FullSourceLoc FullLocation = astContext->getFullLoc(var->getLocStart());
            if((var->hasLocalStorage() || var->isStaticLocal ()))
            {
                if (!var->isDefinedOutsideFunctionOrMethod())
                {
                    if(avoid == 0)
                    {
                        numVariables++;
                        string varName = var->getQualifiedNameAsString();
                        string varType = var->getType().getAsString();
                        const Type *type = var->getType().getTypePtr();
                        if(type->isConstantArrayType())
                        {
                            const ArrayType *Array = type->castAsArrayTypeUnsafe();
                            cout << "Is array of type: "  << Array->getElementType().getAsString() << endl;
                        }
                        REPORT << "[" << FullLocation.getSpellingLineNumber() << "," << FullLocation.getSpellingColumnNumber() << "]Variable Declaration: …