小编She*_*hee的帖子

我想datetime使用下面的SQL查询将值插入表(SQL Server)

insert into table1(approvaldate)values(18-06-12 10:34:09 AM);

但我得到这个错误信息. Incorrect syntax near '10'.

我用引号试了一下

insert into table1(approvaldate)values('18-06-12 10:34:09 AM');

我收到此错误消息 Cannot convert varchar to datetime

请帮忙!谢谢.

我有3张桌子:

Table t1:     Table t2:     Table t3:     
+----+----+   +----+----+   +----+----+   
| i1 | i2 |   | i2 | c2 |   | i1 | c1 |   
+----+----+   +----+----+   +----+----+   
|  1 | 22 |   |  11| cc |   |  1 | e  |   
|  2 | 33 |   |  22| bb |   |  2 | f  |   
|  3 | 11 |   |  33| aa |   |  3 | g  |   
+----+----+   +----+----+   +----+----+   

并且我想使用表t1和列i1和i2从t2和c3从t3中选择colum c2,结果将是thins:

requested Tabel:     
+----+----+   
| c1 …

如何在命令行中逃避可能的连字符,如下所示:

$ for i in db1 db2 db1-db2; do su - postgres -c "psql -c \"alter database \"$i\" with connection limit = 0;\""; done

ALTER DATABASE


ALTER DATABASE ERROR:  syntax error at or near "-" at character 19 LINE 1: alter database db1-db2 with connection limit = 0;
                      ^