小编Ice*_*man的帖子

我想用Spring和Hibernate(以及Maven)构建一个RESTful服务.我首先使用Spring版本4.0.3,一切正常.但我想使用最新版本4.1.0并相应地更改了我的pom.xml.但是在开始时我得到一个错误.你能说出pom.xml应该是什么样的吗？使用spring创建RESTful服务的最佳方法是什么？我找到了一个使用spring-data-rest-webmvc的例子,我正在使用它.有没有更好的办法？

这是错误代码:

    AM org.apache.catalina.core.StandardContext loadOnStartup
    Schwerwiegend: Servlet /spring threw load() exception
    java.lang.NoSuchMethodError: 
    org.springframework.expression.spel.SpelParserConfiguration.<init>
    (Lorg/springframework/expression/spel/SpelCompilerMode;Ljava/lang/ClassLoader;)V
at org.springframework.context.expression.StandardBeanExpressionResolver.<init>(StandardBeanExpressionResolver.java:98)
at        org.springframework.context.support.AbstractApplicationContext.prepareBeanFactory(AbstractApplicationContext.java:553)
at org.springframework.context.support.AbstractApplicationContext.refresh(AbstractApplicationContext.java:455)
at org.springframework.web.servlet.FrameworkServlet.configureAndRefreshWebApplicationContext(FrameworkServlet.java:658)
at org.springframework.web.servlet.FrameworkServlet.createWebApplicationContext(FrameworkServlet.java:624)
at org.springframework.web.servlet.FrameworkServlet.createWebApplicationContext(FrameworkServlet.java:672)
at org.springframework.web.servlet.FrameworkServlet.initWebApplicationContext(FrameworkServlet.java:543)
at org.springframework.web.servlet.FrameworkServlet.initServletBean(FrameworkServlet.java:484)
at org.springframework.web.servlet.HttpServletBean.init(HttpServletBean.java:136)
at javax.servlet.GenericServlet.init(GenericServlet.java:160)
at org.apache.catalina.core.StandardWrapper.initServlet(StandardWrapper.java:1280)
at org.apache.catalina.core.StandardWrapper.loadServlet(StandardWrapper.java:1193)
at org.apache.catalina.core.StandardWrapper.load(StandardWrapper.java:1088)
at org.apache.catalina.core.StandardContext.loadOnStartup(StandardContext.java:5176)
at org.apache.catalina.core.StandardContext.startInternal(StandardContext.java:5460)
at org.apache.catalina.util.LifecycleBase.start(LifecycleBase.java:150)
at org.apache.catalina.core.ContainerBase$StartChild.call(ContainerBase.java:1559)
at org.apache.catalina.core.ContainerBase$StartChild.call(ContainerBase.java:1549)
at java.util.concurrent.FutureTask.run(FutureTask.java:262)
at java.util.concurrent.ThreadPoolExecutor.runWorker(ThreadPoolExecutor.java:1145)
at java.util.concurrent.ThreadPoolExecutor$Worker.run(ThreadPoolExecutor.java:615)
at java.lang.Thread.run(Thread.java:744)

这是我的pom.xml

    <project xmlns="http://maven.apache.org/POM/4.0.0" 
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
    xsi:schemaLocation="http://maven.apache.org/POM/4.0.0 
    http://maven.apache.org/maven-v4_0_0.xsd">
      <modelVersion>4.0.0</modelVersion>
      <groupId>de.rwth-aachen.prime</groupId>
      <artifactId>spring</artifactId>
      <packaging>war</packaging>
      <version>0.0.1-SNAPSHOT</version>
      <name>spring Maven Webapp</name>
      <url>http://maven.apache.org</url>
      <dependencies>
        <dependency>
              <groupId>junit</groupId>
              <artifactId>junit</artifactId>
              <version>4.11</version>
              <scope>test</scope>
        </dependency> …

我正在实现一个RESTful Web服务，该服务将返回所有格式为JSON的内容。我也在使用Spring OAuth2，但是所有错误消息（例如无效访问令牌等）都以XML格式返回。如何将这些OAuth2错误返回为JSON？顺便说一句，访问令牌作为JSON字符串返回。