小编shi*_*ven的帖子

<?php

$wordFrequencyArray = array();

function countWords($file) use($wordFrequencyArray) {  //error here
    /* get content of $filename in $content */
    $content = strtolower(file_get_contents($filename));

这是我正在使用的代码片段.

我在第3行遇到错误.我有所有匹配的括号.可能有什么问题？

<?php
    include_once 'forecastVo.php';
    include_once 'BaseVo.php';
    $count=0;
    $json_url = file_get_contents(
        'http://maps.google.com/maps/api/geocode/json' .
        '?address='jaipur'&sensor=false');                //line 9
    if($json_url){
        $obj = json_decode($json_url,true);

        $obj2= $obj['results'];
    }
?>

我收到一个错误:

解析错误:语法错误,第9行/home/a4101275/public_html/index.php中的意外T_STRING

第9行是我使用的地方file_get_contents.

错误是什么意思,我该如何解决？

我有一小段代码.当我在我的DevC++ gnu编译器上运行它时,它显示以下输出:

 main ()
 {      char b = 'a';
        printf ("%d,", sizeof ('a'));
        printf ("%d", sizeof (b));
        getch ();
 }

输出:4,1

为什么被'a'视为整数,而b被视为只是一个字符常量？

我正在尝试用PHP开发代码判断软件以进行编程分配.我会尝试在需要套接字编程的java服务器上编译代码.我对PHP中的套接字编程有一些了解.我用谷歌搜索,发现一个代码做了一些类似的工作.但我仍然无法获得事情的要点.它实际上是否有效？手册太技术化,无法获得良好的理解

这是一段代码,根据我的理解,我写了评论:

  $socket = fsockopen($compilerhost, $compilerport); // creates connection it returns the file pointer

if($socket) {  // if it returns a file pointer
fwrite($socket, $_POST['filename']."\n");  //write the filename in the file pointer returned by socket and chagne line

$query = "SELECT time, input, output FROM problems WHERE sl='".$_POST['id']."'"; // select input,output,for the problem

$result = mysql_query($query);

$fields = mysql_fetch_array($result);

fwrite($socket, $fields['time']."\n");  // write the time  in the file pointer returned

我不明白fsockopen是如何工作的？如何在这里使用fwrite？

注意:虽然通过代码我无处找到$ compilerhost,$ compilerport变量.

纠正我的疑虑.谢谢提前和原谅英语不好

我想在UBuntu上运行一个php项目.它有一个安装脚本,用于创建mysql数据库.当我尝试运行脚本时,我收到以下错误:

Warning: fopen(dbinfo.php): failed to open stream: Permission denied in /opt/lampp/htdocs/project/install.php on line 12

Warning: fwrite() expects parameter 1 to be resource, boolean given in /opt/lampp/htdocs/project/install.php on line 19

Warning: fclose() expects parameter 1 to be resource, boolean given in /opt/lampp/htdocs/project/install.php on line 20

Warning: include(dbinfo.php): failed to open stream: No such file or directory in /opt/lampp/htdocs/project/install.php on line 21

Warning: include(): Failed opening 'dbinfo.php' for inclusion (include_path='.:/opt/lampp/lib/php') in /opt/lampp/htdocs/project/install.php on line 21

Notice: Undefined variable: host in /opt/lampp/htdocs/project/install.php on …

这是我的代码片段:

    require_once('functions.php');
    include('dbinfo.php');
    connectdb();


$querys= "SELECT 'score' FROM solve WHERE (problem_id='".$_GET['id']."' AND username='".$_SESSION['username']."')";
            $resultscore=mysql_query($querys);
            $scorefetch=mysql_fetch_array($resultscore);
            $subractscore=$scorefetch['score'];
echo $subractscore;

理想情况下,输出应该是存储在数据库的得分字段中的值.但它是打印'

得分了

'..我错在哪里？此外,查询一次只能生成一条记录.