所以,我确信之前已在某处回答过,但我无法在任何地方找到它.希望一些仿制药大师可以提供帮助.
public interface IAnimal{}
public class Orangutan:IAnimal{}
public void ValidateUsing<T>(Action<T> action) where T : IAnimal
{
Orangutan orangutan = new Orangutan();
action(orangutan); //Compile error 1
//This doesn't work either:
IAnimal animal = new Orangutan();
action(animal); //Compile error 2
}
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编辑:基于Yuriy和其他人的建议,我可以做一些演员,如:
public void ValidateUsing<T>(Action<T> action) where T : IAnimal
{
Orangutan orangutan = new Orangutan();
action((T)(IAnimal)orangutan);
//This doesn't work either:
IAnimal animal = new Orangutan();
action((T)animal);
}
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我想要做的是调用ValidateUsing方法,如下所示:
ValidateUsing(Foo);
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不幸的是,如果foo看起来像这样:
private void Foo(Orangutan obj)
{
//Do something
} …Run Code Online (Sandbox Code Playgroud) 我想在GUI中呈现一些文本,并为用户提供双击它的能力.我想抓住这个事件并处理它.
我想这样做:
<TextBlock
Height="39"
TextElement.FontSize="18"
FontFamily="Verdana"
HorizontalAlignment="Left"
VerticalAlignment="Center"
Name="Filelink"
Padding="5,0,0,0"
TextDecorations="Underline"
Text="{Binding Path=FilePath}"/>
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但似乎处理点击并不容易TextBlock.
任何想法是什么是呈现可点击文本的最佳方式.
谢谢.
我使用的是Android Studio 3.1.4.由于我想制作一个Tab Layout,我添加了代码implmentation 'com.android.support design:28.0.0-rc02',它与support.accompatbuild.gradle中的版本相同但出现错误.
我可以知道发生了什么事吗?我该如何解决这个问题?
谢谢你的帮助.
___________________
| field1 | field1 |
|________|________|
| A | E |
| B | D |
| C | C |
| D | B |
| E | A |
|________|________|
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如果可能的话,我做的sql选择就像上面的表有相同的字段相同的表?
select t1.c, t2.c from
(
WITH cte AS
(
SELECT
c,
ROW_NUMBER() OVER(ORDER BY c DESC) AS n,
ROW_NUMBER() OVER(ORDER BY c ASC) AS m
FROM @t
)
SELECT t1.c, t2.c
FROM cte t1
JOIN cte t2 ON t2.n = t1.m
)
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我可以这样做吗?
我正在尝试将纹理加载到libGDX,并且我找到了一个未找到文件的异常.
这是试图加载.png文件的代码.
//Textures
private Texture tiles;
private TextureRegion grassImage;
private TextureRegion dirtImage;
private TextureRegion stoneImage;
//Entities
private Texture entities;
private TextureRegion playerImage;
public WorldRenderer(World world, boolean debug) {
this.world = world;
this.camera = new OrthographicCamera(CAMERA_WIDTH, CAMERA_HEIGHT);
this.camera.position.set(CAMERA_WIDTH/2f, CAMERA_HEIGHT/2f, 0);
this.camera.update();
this.debug = debug;
spriteBatch = new SpriteBatch();
loadTextures();
}
public void loadTextures() {
tiles = new Texture(Gdx.files.internal("tiles.png"));
grassImage = new TextureRegion(tiles, 0, 0, 32, 32);
dirtImage = new TextureRegion(tiles, 0, 64, 32, 32);
stoneImage = new TextureRegion(tiles, 64, 0, 32, …Run Code Online (Sandbox Code Playgroud) 我有三个按钮一个接一个地躺着.我想显示所有按钮的顶部,我点击.所以我在XAML Code中设置了canvas ZIndex.但我想在Code Behind中做到这一点.
我的XAML输出和代码 -

<Button Name="Button1" Canvas.ZIndex="3" Content="Button1" Canvas.Top="100" Width="163" Height="58" FontSize="26" Click="Button1_Click" />
<Button Name="Button2" Canvas.ZIndex="2" Content="Button1" Canvas.Top="100" Canvas.Left="130" Width="163" Height="58" FontSize="26" Click="Button2_Click" />
<Button Name="Button3" Canvas.ZIndex="1" Content="Button1" Canvas.Top="100" Canvas.Left="260" Width="163" Height="58" FontSize="26" Click="Button3_Click" />
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我的XAML输出和代码(检查ZIndex如何更改) -

<Button Name="Button1" Canvas.ZIndex="3" Content="Button1" Canvas.Top="100" Width="163" Height="58" FontSize="26" Click="Button1_Click" />
<Button Name="Button2" Canvas.ZIndex="2" Content="Button1" Canvas.Top="100" Canvas.Left="130" Width="163" Height="58" FontSize="26" Click="Button2_Click" />
<Button Name="Button3" Canvas.ZIndex="1" Content="Button1" Canvas.Top="100" Canvas.Left="260" Width="163" Height="58" FontSize="26" Click="Button3_Click" />
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我如何在Click事件中更改WPF按钮控件中的Canvas.ZIndex属性?
StackOverflow和Untappd这样的网站如何"强制"用户接受他们的权限?
当我尝试使用JavaScript SDK时,我一直在使用范围对象来请求电子邮件地址,但我一直看到"编辑您提供的信息",允许用户不提供他们的电子邮件地址.我甚至尝试过手动构建登录流程,结果相同.
图片:

由于我们允许用户通过Facebook在网站上注册,我们依赖于电子邮件地址在我们的数据库中创建一个帐户.
然而像StackOverflow和Untappd这样的网站没有提供这样的选项,我不得不接受这些权限.
那秘密是什么?我该如何实现这一目标?这是我在某个地方俯瞰的场景吗?还是需要"批准"?
我正在研究laravel 5.2.
当我运行composer install和composer update命令时,它显示错误:
[InvalidArgumentException] Command "optimize" is not defined.
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请让我知道如何解决这个问题.
我有一个 webapi 方法,我想打开 oData 分页等。我按照http://www.asp.net/web-api/overview/odata-support-in-aspnet-web-api/supporting-odata-query-options中的示例进行操作
我的方法如下所示:
public PageResult<UserViewModel> GetUsers(ODataQueryOptions<UserViewModel> options)
{
var settings = new ODataQuerySettings()
{
PageSize = 2
};
var results = UserLogic.GetUsers(userId, UserManager, _db);
var filtered = options.ApplyTo(results, settings);
var pagedResult = new PageResult<UserViewModel>(
filtered as IEnumerable<UserViewModel>,
Request.GetNextPageLink(),
Request.GetInlineCount());
return pagedResult;
}
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计数已填充,下一页链接在那里,并且应用了正确的 oData 选项,即排序顺序等。当我在 api 方法中返回它时,会返回正确的数据,但计数和下一页链接不会出现在我的 json.
我是否缺少打开此功能的设置?
即这是我的 json 响应:
HTTP/1.1 200 OK
Cache-Control: no-cache
Pragma: no-cache
Content-Type: application/json; charset=utf-8
Expires: -1
Server: Microsoft-IIS/8.0
X-RequestID: b215962b-6a4a-431d-9850-7ecbf808538e
X-AspNet-Version: 4.0.30319
X-SourceFiles: =?UTF-8?B?QzpcUmVwb3NpdG9yaWVzXEdpdEh1YlxxbGRyYS1wb3J0YWxccWxkcmEtcG9ydGFsLldlYlxxbGRyYS5iYXNlbGluZS5hcGlcYXBpXHVzZXJz?=
X-Powered-By: ASP.NET
Date: …Run Code Online (Sandbox Code Playgroud) WebClientTestService service = new WebClientTestService() ;
int connectionTimeOutInMs = 5000;
Map<String,Object> context=((BindingProvider)service).getRequestContext();
context.put("com.sun.xml.internal.ws.connect.timeout", connectionTimeOutInMs);
context.put("com.sun.xml.internal.ws.request.timeout", connectionTimeOutInMs);
context.put("com.sun.xml.ws.request.timeout", connectionTimeOutInMs);
context.put("com.sun.xml.ws.connect.timeout", connectionTimeOutInMs);
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请分享差异主要在连接超时和请求超时.
我需要知道这些参数值的推荐值.
设置超时值的标准是什么?