我无法将嵌套的For Generator扁平化为单个For Generator.
我创建了MapSerializer来保存和加载地图.
MapSerializer.scala列表:
import java.io.{ObjectInputStream, ObjectOutputStream}
object MapSerializer {
def loadMap(in: ObjectInputStream): Map[String, IndexedSeq[Int]] =
(for (_ <- 1 to in.readInt()) yield {
val key = in.readUTF()
for (_ <- 1 to in.readInt()) yield {
val value = in.readInt()
(key, value)
}
}).flatten.groupBy(_ _1).mapValues(_ map(_ _2))
def saveMap(out: ObjectOutputStream, map: Map[String, Seq[Int]]) {
out.writeInt(map size)
for ((key, values) <- map) {
out.writeUTF(key)
out.writeInt(values size)
values.foreach(out.writeInt(_))
}
}
}
修改loadMap以在生成器中分配密钥会导致它失败:
def loadMap(in: …我正在使用这个示例 Gradle 插件项目：https : //github.com/AlainODea/gradle-com.example.hello-plugin
当我运行./gradlew publishToMavenLocal 时，它会在 M2_HOME 中创建这些文件：
当我运行./gradlew artifactoryPublish 时，它会记录：
Deploying artifact: https://artifactory.example.com/artifactory/libs-release-local-maven/com/example/hello/gradle-com.example.hello-plugin/0.1-SNAPSHOT/gradle-com.example.hello-plugin-0.1-SNAPSHOT.jar
Deploying artifact: https://artifactory.example.com/artifactory/libs-release-local-maven/com/example/hello/gradle-com.example.hello-plugin/0.1-SNAPSHOT/gradle-com.example.hello-plugin-0.1-SNAPSHOT.pom
Deploying build descriptor to: https://artifactory.example.com/artifactory/api/build
Build successfully deployed. Browse it in Artifactory under https://artifactory.example.com/artifactory/webapp/builds/gradle-com.example.hello-plugin/1234567890123
尝试从另一个 build.gradle 加载插件：
plugins {
id 'java'
id 'com.example.hello' version '0.1-SNAPSHOT'
}
使用 settings.gradle：
pluginManagement {
repositories {
maven {
url 'https://artifactory.example.com/artifactory/libs-release-local-maven/'
}
}
}
导致此错误：
Plugin [id: 'com.example', version: '0.1-SNAPSHOT'] was not found in …我已经将我的第一个 terraform 脚本放在一起，用于在 AWS 上进行资产配置。但是，我无法连接到公有子网中的 EC2 实例
我可以看到所有预期的资源都已创建：子网/实例/路由表/网关等
我已经排除了 provider.tf，因为它包含敏感的秘密。
我的地区是 ap-south-1。
resource "aws_vpc" "vpc1" {
cidr_block = "10.20.0.0/16"
tags = {
name = "tf_vpc"
}
}
# subnets below
resource "aws_subnet" "subnet_public"{
vpc_id = "${aws_vpc.vpc1.id}"
cidr_block = "10.20.10.0/24"
availability_zone = "ap-south-1a"
map_public_ip_on_launch = true
}
resource "aws_subnet" "subnet_private"{
vpc_id = "${aws_vpc.vpc1.id}"
cidr_block = "10.20.20.0/24"
availability_zone = "ap-south-1a"
}
resource "aws_security_group" "sg-web" {
name ="allow80"
description="allows traffic on port 80"
vpc_id ="${aws_vpc.vpc1.id}"
ingress{
from_port = 80
to_port = 80
protocol …我正在学习Java,我不知道这里有什么问题.为什么会发生这种错误？我没有看到任何错误,直到我在第二个"for"循环之前写入"count = 0"行时才实际工作.
这是错误:java.lang.StringIndexOutOfBoundsException:字符串索引超出范围:1
这就是错误发生的地方:
if(mots.get(j).startsWith(searchPhrase.substring(0,1))){
这是整个代码:
import java.util.*;
public class Test {
public static void main(String[] args) {
List<String> mots = new ArrayList<>();
List<String> saida = new ArrayList<>();
mots.add("un");
mots.add("deux");
mots.add("trois");
String searchPhrase = "aaasdeuxctsundesle";
int count = 0;
int countAnula = 0;
int azul = 0;
String anula = "-"; //Tem que fazer cast para char depois
String frase = searchPhrase;
for (int i = 0; i < frase.length(); i++) {
count = 0;
for (int j = …所以2天后(是的,我是一个完整的新手,当涉及到服务器)试图让这个工作我放弃,转向SO寻求帮助:)
我想在启动时启动我的java应用程序,登录到日志文件.而已 :)
start on runlevel [2345]
stop on runlevel [!2345]
#Respawn the process if it crashes
#If it respawns more than 10 times in 5 seconds stop
respawn
respawn limit 10 5
expect fork
script
cd /home/ubuntu/admin/
mvn spring-boot:run > /var/log/upstart/admin.log 2>&1
end script
运行"sudo start admin"工作,我在控制台中得到"管理员启动/运行"..没有创建日志,java应用程序没有启动..？
我错过了什么？
如何在Ubuntu上运行Java作为服务？
terraform 中的以下 2 种样式之间有什么区别，它们相同吗？
vpc_id = aws_vpc.default.id
对比
vpc_id = "${aws_vpc.default.id}"