是否有一种方法,lib或python中的东西,我可以在列表中设置不存在的索引值?像列表中的运行时索引创建一样:
l = []
l[3] = 'foo'
# [None, None, None, 'foo']
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更进一步,使用多维列表:
l = []
l[0][2] = 'bar'
# [[None, None, 'bar']]
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或者使用现有的:
l = [['xx']]
l[0][1] = 'yy'
# [['xx', 'yy']]
Run Code Online (Sandbox Code Playgroud) 另一个问题是如何在sqlalchemy上使用OVER子句:
但是如何使用ORM呢?我有类似的东西:
q = self.session.query(self.entity, func.count().over().label('count_over'))
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q.all()使用以下消息调用时失败:
sqlalchemy.exc.InvalidRequestError:
Ambiguous column name 'count(*) OVER ()' in result set! try 'use_labels' option on select statement
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我怎么解决这个问题?
我正在使用多维数组,并且我注意到postgres需要强制转换表达式以插入值,例如:
CREATE TABLE test (
pay integer[]
);
CREATE TABLE
INSERT INTO test values (ARRAY[NULL]);
ERROR: column "pay" is of type integer[] but expression is of type text[]
LINE 1: INSERT INTO test values (ARRAY[NULL]);
^
HINT: You will need to rewrite or cast the expression.
INSERT INTO test values (ARRAY[NULL::integer]); -- How to do this on SqlAlchemy ?
INSERT 0 1 -- ARRAY[NULL]::integer[] would also works
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这就是我添加对象时SqlAlchemy所做的事情,如果VALUE为NULL,则不会进行类型转换。这是我的代码的一部分:
from sqlalchemy.dialects.postgresql import ARRAY
class Test (Base):
__tablename__ = 'test'
pay = …Run Code Online (Sandbox Code Playgroud) 有没有办法在Python中过滤嵌套字典,这样我只能看到我指定的键?例子:
x = {
"field": [
{
"nm_field": "ch_origem_sistema_chave",
"inf_tabelado": {
"dropdown_value": "",
"dropdown_key": "",
"url_lista": "",
"chave_relacional": ""
},
},
{
"nm_field": "ax_andamento_data",
"inf_tabelado": {
"dropdown_value": "",
"dropdown_key": "",
"url_lista": "",
"chave_relacional": ""
},
}
],
"_metadata": {
"dt_reg": "22/01/2014 16:17:16",
"dt_last_up": "10/04/2014 16:30:44",
},
"url_detalhes": "/DetalhesDocsPro.aspx",
"url_app": "/docspro",
}
y = filter(x, ['dropdown_value', 'nm_field', 'url_app', 'dt_reg'])
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那么 var y 会是这样的:
{
"field": [
{
"nm_field": "ch_origem_sistema_chave",
"inf_tabelado": {
"dropdown_value": "",
},
},
{
"nm_field": "ax_andamento_data",
"inf_tabelado": {
"dropdown_value": …Run Code Online (Sandbox Code Playgroud)