小编mom*_*raw的帖子

我有3个选择框,我想将所选值复制到第二个选择框,从第二个框复制到第三个选择框.在3选择框中,选择框将具有相同的选项.

我该怎么做？

JSFiddle http://jsfiddle.net/andrewvmail/27rFQ/3/

 A:<select id="inputsa">
    <option id="inputa"  name="input[1][]">A</option>
    <option id="inputb" name="input"> B</option>
    <option id="inputc"  name="input[2][]"> C</option>
</select> 
B:<select id="inputsb">
    <option id="inputa"  name="input[1][]">A</option>
    <option id="inputb" name="input"> B</option>
    <option id="inputc"  name="input[2][]"> C</option>
</select> 
C:<select id="inputsc">
    <option id="inputa"  name="input[1][]">A</option>
    <option id="inputb" name="input">B</option>
    <option id="inputc"  name="input[2][]">C</option>
</select> 

<br>    




    <input id="copyAtoB" type="button" value="Copy A to B" onclick="functionCopyAtoB();">
        <br>
    <input id="copyBtoC" type="button" value="Copy B to C" onclick="functionCopyBtoC();">

干杯

我有这样的多个复选框

<input name="1[]" type="checkbox">
<input name="1[]" type="checkbox">
<input name="2[]" type="checkbox">
<input name="2[]" type="checkbox">
<input name="3[]" type="checkbox">
<input name="4[]" type="checkbox">

如何将onclick绑定到所有这些复选框.并运行一个函数..让我们说一个提示"你单击列出的复选框之一"

 $("input").click() {

            return confirm("you click one of the listed checkbox?");

    });

这不起作用

SELECT     
   Event.Id, Event.Title, Event.StartDateTime, Event.DeadlineDate, 
   [File].ShortFileName, People.Initials
FROM         
   People 
INNER JOIN
   People2Event ON People.Id = People2Event.PeopleId 
RIGHT OUTER JOIN
   [File] 
INNER JOIN
   File2Event ON [File].Id = File2Event.FileId 
RIGHT OUTER JOIN
   Event ON File2Event.EventId = Event.Id ON People2Event.EventId = Event.Id

我有这个声明它可以打印所有记录.下面不起作用,它与where函数的声明相同.有谁知道如何解决？

SELECT     
   Event.Id, Event.Title, Event.StartDateTime, Event.DeadlineDate, 
   [File].ShortFileName, People.Initials
FROM         
   People 
INNER JOIN
   People2Event ON People.Id = People2Event.PeopleId 
RIGHT OUTER JOIN
   [File] 
INNER JOIN
   File2Event ON [File].Id = File2Event.FileId 
RIGHT OUTER JOIN
   Event ON File2Event.EventId = Event.Id ON People2Event.EventId = Event.Id
WHERE …