我希望当用户打开应用程序时: 如果它过去已经连接,它会直接打开应用程序,否则如果它刚刚安装它,它会打开一个登录页面
在 Android studio 中我确实喜欢这样:
@Override
protected void onStart() {
super.onStart();
SharedPreferencesOpti sp = new SharedPreferencesOpti(this);
boolean isConnected = sp.getBooleanSharedPreferences("isConnected");
UserModel.setConnected(isConnected);
if (!UserModel.isConnected())
{
Intent intent = new Intent(MainActivity.this, LoginActivity.class);
startActivity(intent);
}
}
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这是我的颤振代码:
class MyApp extends StatefulWidget {
const MyApp({Key? key}) : super(key: key);
@override
State<MyApp> createState() => _MyAppState();
}
class _MyAppState extends State<MyApp> {
// This widget is the root of your application.
@override
Widget build(BuildContext context) {
return MaterialApp(
debugShowCheckedModeBanner: false,
title: 'Flutter …Run Code Online (Sandbox Code Playgroud) 我想问一下,当您点击 Instagram、Tiktok 等图像时,如何为图标的大小设置动画效果...
这是我尝试过的(以及许多其他事情)但没有成功。
GestureDetector(
onDoubleTap: (){
setState(() {
_showLikeAnimation = true;
_sizeFavoriteAnimation = 60.0; //old value is 20.0
});
},
child: Stack(
alignment: AlignmentDirectional.center,
children: [
_imagePost(),
AnimatedSize(curve: Curves.easeIn, duration: const Duration(seconds: 2), child: Icon(Icons.favorite, size: _sizeFavoriteAnimation))
],
)),
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你有什么想法吗?