我正在尝试通过注释将无状态EJB注入我的JAX-RS Web服务.不幸的是,EJB是公正的null,NullPointerException当我尝试使用它时,我得到了它.
@Path("book")
public class BookResource {
@EJB
private BookEJB bookEJB;
public BookResource() {
}
@GET
@Produces("application/xml")
@Path("/{bookId}")
public Book getBookById(@PathParam("bookId") Integer id)
{
return bookEJB.findById(id);
}
}
我究竟做错了什么？
以下是有关我的机器的一些信息:
你们能展示一些有用的例子吗？
我正在开发自己的PHP库,我想从我的API调用RESTful Web服务.这可以在PHP中完成,如果是这样,这样做的基础是什么？
我正在使用android studio 3.4.1，我的kotlin版本是1.3.31。我有一个扑扑的应用程序。尝试将cloud_firestore添加到我的应用程序时。我有以下问题。我的Android Studio Kotlin版本与build.gradle完全相同。有什么建议吗？
这是我的buld.gradle：
buildscript {
ext.kotlin_version = '1.3.31'
repositories {
google()
jcenter()
}
dependencies {
classpath 'com.android.tools.build:gradle:3.4.1'
classpath "org.jetbrains.kotlin:kotlin-gradle-plugin:$kotlin_version"
// for firebase
classpath 'com.google.gms:google-services:4.2.0'
}
}
错误讯息：
org.gradle.execution.MultipleBuildFailures: Build completed with 2 failures.
at org.gradle.initialization.DefaultGradleLauncher.finishBuild(DefaultGradleLauncher.java:194)
at org.gradle.initialization.DefaultGradleLauncher.doBuildStages(DefaultGradleLauncher.java:165)
Cause 1: org.gradle.internal.exceptions.LocationAwareException: New Gradle Sync is not supported due to containing Kotlin modules using an unsupported plugin version
at org.gradle.initialization.exception.DefaultExceptionAnalyser.transform(DefaultExceptionAnalyser.java:99)
at org.gradle.initialization.exception.DefaultExceptionAnalyser.collectFailures(DefaultExceptionAnalyser.java:65)
at org.gradle.initialization.exception.MultipleBuildFailuresExceptionAnalyser.transform(MultipleBuildFailuresExceptionAnalyser.java:39)
at org.gradle.initialization.exception.StackTraceSanitizingExceptionAnalyser.transform(StackTraceSanitizingExceptionAnalyser.java:29)
at org.gradle.initialization.DefaultGradleLauncher.finishBuild(DefaultGradleLauncher.java:194)
at org.gradle.initialization.DefaultGradleLauncher.doBuildStages(DefaultGradleLauncher.java:165)
at org.gradle.initialization.DefaultGradleLauncher.executeTasks(DefaultGradleLauncher.java:134)
at org.gradle.internal.invocation.GradleBuildController$1.execute(GradleBuildController.java:58)
at org.gradle.internal.invocation.GradleBuildController$1.execute(GradleBuildController.java:55)
at org.gradle.internal.invocation.GradleBuildController$3.create(GradleBuildController.java:82)
at …我是python的新手.我需要一个简单明了的脚本来为每个列表元素添加引号.让我解释一下.这是我的代码.
parameters = ['a', 'b', 'c']
query = "SELECT * FROM foo WHERE bar IN (%s)" % (', '.join(parameters))
我想用它来查询.但结果是无效查询.这是结果.
SELECT * FROM foo WHERE bar IN (a, b, c, d)
我想这样:
SELECT * FROM foo WHERE bar IN ('a', 'b', 'c', 'd')
如何在连接元素时添加引号.
在JavaScript中,如何测试一个数组是否具有另一个数组的元素？
arr1 = [1, 2, 3, 4, 5]
[8, 1, 10, 2, 3, 4, 5, 9].function_name(arr1) # => true
我想在javascript中将下面的字符串转换为数组.
{a:12, b:c, foo:bar}
如何将此字符串转换为对象数组？有什么好主意吗？
我是铁杆新手.我在lib目录中有一个设置,如下所示:
lib/
blog/
core/
search/
base.rb
base.rb也定义了Base类:
module Blog
module Core
module Search
class Base
attr_accessor :properties
def initialize(params)
@properties = {}
end
end
end
end
end
我的application.rb中有以下代码
config.autoload_paths += Dir["#{config.root}/lib/**/"]
当我将它包含在posts控制器中时,我会收到以下错误:
LoadError in PostsController#index
Expected /home/usr/code/blog/lib/blog/core/search/base.rb to define Base
任何的想法？我正在使用rails 3.2.5和RVM.谢谢你的建议.
更新:添加了我的完整堆栈:
Started GET "/admin/posts" for 127.0.0.1 at 2012-06-08 21:06:18 +0800
LoadError (Expected /home/usr/code/blog/lib/blog/core/search/base.rb to define Base):
app/controllers/admin/base_controller.rb:5:in `<top (required)>'
app/controllers/admin/posts_controller.rb:6:in `<top (required)>'
Rendered /home/usr/.rvm/gems/ruby-1.9.3-p194@rails-3.2.5/gems/actionpack-3.2.5/lib/action_dispatch/middleware/templates/rescues/_trace.erb (1.9ms)
Rendered /home/usr/.rvm/gems/ruby-1.9.3-p194@rails-3.2.5/gems/actionpack-3.2.5/lib/action_dispatch/middleware/templates/rescues/_request_and_response.erb (0.6ms)
Rendered /home/usr/.rvm/gems/ruby-1.9.3-p194@rails-3.2.5/gems/actionpack-3.2.5/lib/action_dispatch/middleware/templates/rescues/diagnostics.erb within rescues/layout (7.0ms)
我是Jenkins CI的新手.我在我的远程Jenkins中安装RVM,当我执行下面的shell时.
#!/bin/bash -x
source ~/.bashrc
rvm use 1.9.3@rails-3.2.3
我得到以下错误.
+ source /var/lib/jenkins/.bashrc
++ PATH=/usr/local/bin:/usr/bin:/bin:/usr/local/games:/usr/games:/var/lib/jenkins/.rvm/bin:/var/lib/jenkins/.rvm/bin
+ rvm use 1.9.3@rails-3.2.3
RVM is not a function, selecting rubies with 'rvm use ...' will not work.
You need to change your terminal settings to allow shell login.
Please visit https://rvm.io/workflow/screen/ for example.
这是什么意思？我什么都不知道.请帮我.
更新:我尝试下面的脚本,但我仍然得到错误:
#!/bin/bash -x
source /home/zeck/.bashrc
[[ -s ".rvmrc" ]] && source .rvmrc
export RAILS_ENV=test
bundle install
错误:
/tmp/hudson457106939700368111.sh: line 5: bundle: command not found
Build step 'Execute shell' marked …我需要在python中使用sympy计算下面的表达式？
exp = '(a+b)*40-(c-a)/0.5'
在a=6,b=5,c=2这种情况下如何使用Python sympy计算表达式？请帮我.