小编Sam*_*m P的帖子

我正在尝试编写一个带有两个模板类型的类.该类继承自接口.请参阅以下代码.

#include <iostream>
#include <string>

template <typename T>
class IObserver {
 public:
  virtual void Next(const T& value) noexcept = 0;
};

template <typename T1, typename T2>
class BinaryObserver : public IObserver<T1>, public IObserver<T2> {
 public:
  void Next(const T1& value) noexcept override{};

  void Next(const T2& value) noexcept override{};
};

int main() {
  // This is OK
  BinaryObserver<int, float> mc1;
  mc1.Next(0);
  mc1.Next(0.0f);

  // This fails to compile with "multiple overloads"
  BinaryObserver<int, int> mc2;
  mc2.Next(0);
  mc2.Next(0);
}

我遇到麻烦的时候T1是同一类型的T2.显然这意味着Next …

我正在尝试实现登录变异.该变异验证提供的id_token并通过会话记录用户.突变本身有效(用GraphiQL验证),但我遇到了将它与Relay集成的问题.

当用户登录时,整个中继存储可能会被更改,因为"viewer"是根查询.但我不想在胖查询中列出我的整个查询树.能够以某种方式清除整个商店会很好,但我没有看到这样做的方法react-router-relay.

中继突变:

export default class LoginMutation extends Relay.Mutation {
  getMutation() {
    return Relay.QL`mutation {login}`;
  }

  getVariables() {
    return {
      id_token: this.props.id_token
    };
  }

  getFatQuery() {
    // TODO: list everything?
    return Relay.QL`
      fragment on LoginPayload {
        viewer
      }
    `;
  }

  getConfigs() {
    return []; // TODO: not sure what to return...
  }
}

用法:

Relay.Store.commitUpdate(new LoginMutation({id_token}), {
        onSuccess: (resp) => {
          history.push('/');
        }
      });

GraphQL架构:

input LoginInput {
  id_token: String!
  clientMutationId: String!
}

type LoginPayload {
  viewer: Viewer …