小编atr*_*ona的帖子

See here are some modules in alphabetical order by default in the admin sidebar

Authentication and Authorization Data/Questions/Surveys/Website admin

I want to rearrange the order how can I do that. ? I know in the Django world it does not matter. But our client requested to do that. So we need help with how we can do that.

我有一个带有数字的对象数组，但类型是 string ，我想将它们全部相加。

按照之前建议的堆栈溢出答案，我正在这样做。

// Here the data has an array of goods which contains
// amount objects and i want to calculate to sum of amount objects
Total Invoice Price:
{data.goods
   ? data.goods.map((item) => (
    <div key={item.id}>
     <div>{parseInt(item.amount).reduce((a, b) => a + b, 0)}</div>
       </div >
       ))
     : null}

但我收到错误TypeError: parseInt(...).reduce is not a function，如何解决这个问题？

我正在尝试获取嵌套数组的总和。数组结构是这样的：

const arr = [
  { question: 'A', parentId: 1, weightage: 10, child: [] },
  {
    question: 'B',
    parentId: 4,
    weightage: 0,
    child: [{ id: 4, sub_question: 'X', weightage: 55 }]
  },
  { question: 'C', parentId: 5, weightage: 20, child: [] }
]

在这里您可以看到一个问题，然后是一个带有子问题的子数组。两者都有一个名为权重的键。我想将所有权重值计算为总和。

我正在使用这种方法

  const sum = (value, key) => {
    if (!value || typeof value !== 'object') return 0
    if (Array.isArray(value)) return value.reduce((t, o) => t + sum(o, key), 0)
    if (key in value) return value[key]
    return sum(Object.values(value), …

我需要修改nginx.conf来增加client_max_body_size . 在 AWS 文档上。这里他们给出了如何修改配置的示例。但他们做了很多我不想做的事情。

https://docs.aws.amazon.com/elasticbeanstalk/latest/dg/java-se-nginx.html

user                    nginx;
error_log               /var/log/nginx/error.log warn;
pid                     /var/run/nginx.pid;
worker_processes        auto;
worker_rlimit_nofile    33282;

events {
    worker_connections  1024;
}

http {
  include       /etc/nginx/mime.types;
  default_type  application/octet-stream;

  log_format  main  '$remote_addr - $remote_user [$time_local] "$request" '
                    '$status $body_bytes_sent "$http_referer" '
                    '"$http_user_agent" "$http_x_forwarded_for"';

  include       conf.d/*.conf;

  map $http_upgrade $connection_upgrade {
      default     "upgrade";
  }

  server {
      listen        80 default_server;
      root /var/app/current/public;

      location / {
      }git pull
      

      location /api {
          proxy_pass          http://127.0.0.1:5000;
          proxy_http_version  1.1;

          proxy_set_header    Connection          $connection_upgrade;
          proxy_set_header    Upgrade             $http_upgrade;
          proxy_set_header    Host                $host; …

我有一个返回布尔值的对象列表，如下所示

badges = [{"is_staff": self.sender.is_staff},
                  {"is_vendor": self.sender.is_vendor}, {"is_trader": self.sender.is_trader}]

# or we can write this like that; 
badges = [{"is_staff": True}, {"is_vendor": False}, {"is_trader": True}]

我想以这个优先级返回用户徽章；is_staff 具有最高优先级，然后是供应商，然后是交易者。

如果用户拥有所有徽章，那么我只想将 is_staff 的徽章作为字符串值返回到 = 'staff'，因为它具有最高优先级。

喜欢

badge = 'staff'

我有这个功能可以使用。但没有找到返回我想要的值的方法。

@property
def badge(self):
    "Returns the user's designation if the user is Staff, Vendor, Trader."
    badges = [{"is_staff": self.sender.is_staff},
              {"is_vendor": self.sender.is_vendor}, {"is_trader": self.sender.is_trader}]
    badge = ''
    # need help there to find the value on the basis of badges 
    return badge