小编Bru*_*rra的帖子

我在Rails主应用程序上运行我的帮助程序测试时遇到错误(带有更多插件)

 1) MenuHelper maintence menu 
   Failure/Error: before { menu = build_menu_maintence() }
 NameError:
   undefined local variable or method `main_app' for #<RSpec::Core::ExampleGroup::Nested_3::Nested_1:0x007f92f561f280>
 # ./app/helpers/menu_helper.rb:37:in `eval'
 # (eval):1:in `block in build_menu_items'
 # ./app/helpers/menu_helper.rb:37:in `eval'
 # ./app/helpers/menu_helper.rb:37:in `block in build_menu_items'
 # ./app/helpers/menu_helper.rb:23:in `each'
 # ./app/helpers/menu_helper.rb:23:in `build_menu_items'
 # ./app/helpers/menu_helper.rb:15:in `build_menu'
 # ./app/helpers/menu_helper.rb:48:in `build_menu_maintence'
 # ./spec/helpers/menu_helper_spec.rb:11:in `block (3 levels) in <top (required)>'

谢谢你的进步,

用ruby方式做这个更优雅的方式？我想这很好:

([0]*5).collect { Factory :customer_pj }

要么

 (1..5).to_a.collect { Factory :customer_pj }

我的目标是初始化5个客户并投入阵列.我碰巧let在一个rspec测试中这样做.