小编D T*_*D T的帖子

如果我添加一个EditTextXML,我可以设置textCursorDrawable="@null":

<EditText
    android:id="@+id/txtE3Casecode4"
    android:layout_width="30dp"
    android:layout_height="wrap_content"
    android:layout_alignParentTop="true"
    android:background="#C7C7C5"
    android:textCursorDrawable="@null"
    android:ems="10"
    android:inputType="number"
    android:maxLength="2"
    android:text="01"
    android:textColor="#000000" />

现在我画一个EditTextJava.我想要设定android:textCursorDrawable="@null".

LinearLayout.LayoutParams paramtext = new LinearLayout.LayoutParams(
    LinearLayout.LayoutParams.FILL_PARENT,
    LinearLayout.LayoutParams.WRAP_CONTENT);
EditText txtOther = new EditText(this);
txtOther.setLayoutParams(paramtext);
txtOther.setBackgroundColor(Color.WHITE);
txtOther.setTextColor(Color.BLACK);
txtOther.setId(99999);
// txtOther.setCursorDrawable ?                                

怎么设置它？

我的查询:

DELETE a FROM TR_ContactResultRecord  a
INNER JOIN TR_Case  b on (a.FireStationCode=b.FireStationCode and a.CaseNo=b.CaseCode )
WHERE b.Update_DateTime <=20140628134416

它显示错误: [Err] 1 - near "a": syntax error

如何删除表内连接与Sqlite中的其他表？

在centos6.2默认是php 5.3.3.但我想安装PHP 5.4.1.你能帮助我吗？如何在centos6.2中安装php5.4.1？谢谢!

因为startActivityForResult已被弃用。所以我替换startActivityForResult为registerForActivityResult

这是我的代码：

ActivityResultLauncher<Intent> someActivityResultLauncher = registerForActivityResult(
            new ActivityResultContracts.StartActivityForResult(),
            new ActivityResultCallback<ActivityResult>() {
                @Override
                public void onActivityResult(ActivityResult result) {
                    if (result.getResultCode() == Activity.RESULT_OK) {
                        // There are no request codes
                        //Intent data = result.getData();
                        //doSomeOperations();
                    }
                }
            });

因为我调用了多个 Activity：

旧版本：

 Intent myinten = new Intent(MainActivity.this, MainActivity2.class);
 startActivityForResult(myinten, 111);

Intent myinten = new Intent(MainActivity.this, MainActivity3.class);
startActivityForResult(myinten, 222);

新版本：

Intent myinten = new Intent(MainActivity.this, MainActivity2.class);
someActivityResultLauncher.launch(myinten);

Intent myinten = new Intent(MainActivity.this, MainActivity3.class);
someActivityResultLauncher.launch(myinten);

我们可以使用“registerForActivityResult”发送和获取“requestCode”吗？

这是文件test1.php:

 <?php    
    set_time_limit(0);
    for($i= 1;$i<5000 ;$i++){

        $comm_sjis = "echo 'test'";
        $result = exec($comm_sjis);

    }
    unset($result);
    echo 'ok';

这是文件test2.php:

<?php

set_time_limit(0);

function write_txt($str)
{
    $filepath = 'E:/temp/test.xml';
    if (($fp = @fopen($filepath, "a")) === false) {
        return;
    }

    if (!flock($fp, LOCK_EX)) {
        @fclose($fp);
        return;
    }

    if (fwrite($fp, $str . "\n") === false) {
        @flock($fp, LOCK_UN);
        @fclose($fp);
        return;
    }

    if (!fflush($fp)) {
        @flock($fp, LOCK_UN);
        @fclose($fp);
        return;
    }

    if (!flock($fp, LOCK_UN)) {
        @fclose($fp);
        return;
    }

    if (!fclose($fp)) {
        return;
    } …

我想在Android中自定义一个对话框.我知道如何设置对话框的标题:

dialog.setTitle("O message");

现在我想在标题前面设置图标.我怎样才能做到这一点？

Dialog dialog;
dialog = new Dialog(this);
dialog.setContentView(R.layout.layouterror22);      
dialog.setTitle("O message");

代码 TDBACore.vb:

Imports System.ComponentModel
Imports System.Data

<EditorBrowsable(EditorBrowsableState.Never)> _
Public MustInherit Class TDBACore        
    Private Shared FRefCount As Integer

    Friend Shared FIsBeginTran As Boolean = False

    Friend Shared FConnection As IDbConnection

    Friend Shared FTransaction As IDbTransaction

    Private disposedValue As Boolean

    Friend Shared iRecheckTimeout As Integer
    Friend Shared iConnectionTimeOut As Integer

    Friend MustOverride Function CreateConnection() As IDbConnection

    Public Sub New()
        Me.disposedValue = False
        If TDBACore.FRefCount = 0 Then
            TDBACore.FConnection = Me.CreateConnection()
        End If
        TDBACore.FRefCount += 1

    End Sub

   Friend Shared Sub OpenConnection(ByVal …

我有一些列类型int,但值为空.所以我想在插入数据库时​​将empty转换为null.我用代码:

function toDB($string) {
    if ($string == '' || $string == "''") {
        return 'null';
    } else {
        return "'$string'";
    }
}

//age,month,year is type integer.
$name="Veo ve";
$age='10';
$month='';
$year='';
    $query="Insert Into tr_view(name,age,month,year) values ({toDB($name)},{toDB($age)},{toDB($month)},{toDB($year)})
 $db->setQuery($query);
 $result= $db->query();

但它显示错误:

 pg_query(): Query failed: ERROR: syntax error at or near "{" LINE 153: {toDB(10)}, ^ in...

为什么？

此查询适用于PostgreSQL:

  Select    ot.MCode,array_to_string(array_agg(tk1.TName || ',' || ot.TTime), ' - ') as oujyu_name_list
    From    TR_A ot
    inner join MS_B tk1 on ot.Code = tk1.Code
    Where   ot.Code in (Select Code From TR_C ) 
    Group byot.MCode

但它在SQLite中不起作用,因为SQLite没有这个array_agg()功能.如何将此查询转换为SQLite？

在一个函数中，我有SELECT一个字符串查询，例如：

sql='SELECT * FROM A'

我想执行以下sql输出结果：SELECT * FROM A

如何sql在 PostgreSQL 中执行字符串？