为什么d不是一个对象?以及如何访问这些文本对象?(以下代码错误)
d3.selectAll("svg text").each(function(d, i) {
d.text("New");
});
Run Code Online (Sandbox Code Playgroud) 我遇到了在Python的性能问题,我的一个朋友建议我用用Cython搜索更长时间后,我发现这个代码在这里
蟒蛇:
def test(value):
for i in xrange(value):
z = i**2
if(i==1000000):
print i
if z < i:
print "yes"
test(10000001)
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用Cython:
def test(long long value):
cdef long long i
cdef long long z
for i in xrange(value):
z = i**2
if(i==1000000):
print i
if z < i:
print "yes"
test(10000001)
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在我执行两个代码之后,令人惊讶的是我通过Cython实现了100倍的加速
为什么只是通过添加变量声明来实现这种加速?另外我应该提到波纹管代码性能与Cython中的Python相同.
用Cython:
def test(long long value):
for i in xrange(value):
z = i**2
if(i==1000000):
print i
if z < i:
print "yes"
test(10000001)
Run Code Online (Sandbox Code Playgroud) 我与卡桑德拉玩,我配置了两个虚拟机上的两个节点,两个节点都是干净的,令牌的数量是256,节点检测到对方,但都拥有100%,我应该怎么做负载均衡?
Starting NodeTool
Datacenter: 16
===============
Status=Up/Down
|/ State=Normal/Leaving/Joining/Moving
-- Address Load Owns (effective) Host ID Token
UN 172.16.47.183 104.24 KB 100.0% ace3bddb-dd03-4ab9-88ef-49b99a1289ae -9170032883711216954
UN 172.16.47.130 128.96 KB 100.0% a14ee1fd-a993-43a5-9994-183f25de997f -9181340211822384770
Run Code Online (Sandbox Code Playgroud) 我有两个节点Cassandra集群.为了测试Cassandra我构建了一个File表(Fid Integer,Sid Integer),哪个Fid是关键.我在Sid上建立索引,插入速率在1秒内约为10,000.但是当我从表中选择性能很糟糕时,对于像1000这样的低限制它会产生错误,下面是我的示例代码,
from cassandra.cluster import Cluster
cluster = Cluster(['127.0.0.1'])
session = cluster.connect('myk')
rows = session.execute('SELECT * FROM File WHERE sid = 1 limit 1000')
for user_row in rows:
print user_row
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错误信息是:
Traceback (most recent call last):
File "Test.py", line 5, in <module>
rows = session.execute('SELECT * FROM File WHERE sid = 1 limit 1000')
File "build\bdist.win32\egg\cassandra\cluster.py", line 1065, in execute
File "build\bdist.win32\egg\cassandra\cluster.py", line 2427, in result
cassandra.OperationTimedOut: errors={}, last_host=172.16.47.130
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通过改变
rows = session.execute('SELECT * FROM File WHERE sid = …Run Code Online (Sandbox Code Playgroud)