小编The*_*tor的帖子

我正在尝试将此 for 循环向量化。使用 Rpass 标志后，我收到以下评论：

int someOuterVariable = 0;

for (unsigned int i = 7; i != -1; i--)
{
  array[someOuterVariable + i] -= 0.3 * anotherArray[i];
}

Remark:
The cost-model indicates that vectorization is not beneficial
the cost-model indicates that interleaving is not beneficial

我想了解这意味着什么。“交错不是有益的”是否意味着数组索引不正确？