小编Aji*_*jit的帖子

我正在尝试动态设置和编写excel文件.这是我的代码

import pandas as pd
import copy

class OutputWriter(object):

    def __init__(self, fmt_func, sheet_name='data'):
        '''
        Initializing...
        '''
        # NOTICE: Initialising with path set None since I do not know path yet
        wrt = pd.ExcelWriter(None, engine='xlsxwriter')
        self._writer = fmt_func(wrt, sheet_name)
        self._sheet_name = sheet_name

    def save(self, df, o_path):
        '''
        Save the file to a path
        '''
        # setting path in writer before saving
        self._writer.path = o_path
        df.to_excel(self._writer, sheet_name=self._sheet_name)
        self._writer.save()

# Change first row color to blue
def fmt_func_blue(wrt, sheet_name):
    # ERROR Cannot clone …

我试图在java中打印金字塔看起来像这样: -

                    9
                  8 9 8
                7 8 9 8 7
              6 7 8 9 8 7 6
            5 6 7 8 9 8 7 6 5
          4 5 6 7 8 9 8 7 6 5 4 
        3 4 5 6 7 8 9 8 7 6 5 4 3 
      2 3 4 5 6 7 8 9 8 7 6 5 4 3 2 
    1 2 3 4 5 6 7 8 9 8 7 6 5 4 …

我目前setup.py有三个console_scripts条目:

console_scripts=[
    ‘myapp-dev=bin/run:dev',
    ‘myapp=bin/run:prod',
    ‘myapp-cmd-line=bin/run:cmd'
]

run.py 包含这些的简单函数:

#!/usr/bin/env python

myapp = App()

def dev():
    myapp.run(mode='dev')

def prod():
    myapp.run()

def cmdline():
    myapp.run(mode='cmd')

有没有办法可以.exe为上面的每一个创建3个单独的文件

我正在努力学习如何使用fread和fwrite.在这里,我试图在标准输出上打印文件的内容.

#include <stdio.h>

int main()

{
FILE *fp; 
fp = fopen("largest.c", "r+");
int c = fwrite(fp, sizeof(fp), 1, stdout);

printf("Output is 1 if write succesful! : %d\n", c);

return 0;
}

这不起作用.在屏幕上显示一些乱码.为什么？

您好我正在尝试将正则表达式与a匹配FilePath来过滤我的文件列表

import Text.Regex.Posix
import System.FilePath

escapePath path = foldr (&&) True $ map (\pat -> not $  (path =~ pat :: Bool)) patterns
                   where
                       patterns = ["\\.",  "\\.\\.", {-- So on --}]

我相信map并folds会在返回值之前遍历完整列表.

做这样的事我可以避免使用折叠

escapePath path = not $ elem True (map (\pat -> (path =~ pat :: Bool)) patterns)
                    where
                       patterns = ["\\.",  "\\.\\.", {-- continued --}]

但在搜索值之前,我仍会匹配所有模式的路径

如何通过在第一次匹配时返回值来提高函数效率？