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使用改进的android调用WSDL Web服务

我试图在我的应用程序中使用retrofit来调用WSDL webservice

像这样

public static String callWebservice(String username,String password)
    {

        String soapMessage="<?xml version=\"1.0\" encoding=\"utf-8\"?>"+
                "<Envelope xmlns=\"http://schemas.xmlsoap.org/soap/envelope/\">"+
                "<Body>"+
                "<AuthenticateUser xmlns=\"http://tempuri.org/\">"+
                "<userName>"+username+"</userName>"+
                "<password>"+Helper.md5(password).toUpperCase(Locale.getDefault())+"</password>"+
                "</AuthenticateUser>"+
                "</Body>"+
                "</Envelope>";

        RequestInterceptor requestInterceptor = new RequestInterceptor() {
              @Override
              public void intercept(RequestFacade request) {
               // request.addHeader("User-Agent", "Retrofit-Sample-App");
                request.addHeader("SOAPAction", "http://tempuri.org/IAuthenticate/AuthenticateUser");
                request.addHeader("Content-Type", "application/soap+xml;charset=utf-8");
                request.addHeader("Content-Type", "text/xml;charset=utf-8");
              }
            };

            RestAdapter restAdapter = new RestAdapter.Builder()
              .setEndpoint(Constants.WEBSERVICE_URL)
              .setRequestInterceptor(requestInterceptor)
              .build();

            LoginApi loginApi=restAdapter.create(LoginApi.class);

            loginApi.getLogin(soapMessage,new Callback<String>() 
            {

                @Override
                public void success(String arg0, Response arg1)
                {

                    Helper.Log("Response==>", arg0);

                }

                @Override
                public void failure(RetrofitError arg0) 
                {
                    Helper.Log("error==>", arg0.toString());

                } …
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android wsdl web-services retrofit

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