所以现在我至少得到以下代码的回调...
- (void)viewDidLoad {
[super viewDidLoad];
mapView=[[MKMapView alloc] initWithFrame:self.view.frame];
//mapView.showsUserLocation=TRUE;
mapView.delegate=self;
[self.view insertSubview:mapView atIndex:0];
NSLog(@"locationServicesEnabled: %@", [CLLocationManager locationServicesEnabled] ? @"YES":@"NO");
CLLocationManager *newLocationManager = [[CLLocationManager alloc] init];
[newLocationManager setDesiredAccuracy:kCLLocationAccuracyBest];
[newLocationManager setDistanceFilter:kCLDistanceFilterNone];
[self setLocationManager:newLocationManager];
[[self locationManager] setDelegate:self];
[[self locationManager] startUpdatingLocation];
NSLog(@"Started updating Location");
}
- (void)locationManager:(CLLocationManager *)manager didUpdateToLocation:(CLLocation *)newLocation fromLocation:(CLLocation *)oldLocation {
NSLog(@"Did update to location");
mStoreLocationButton.hidden=FALSE;
location=newLocation.coordinate;
MKCoordinateRegion region;
region.center=location;
MKCoordinateSpan span;
span.latitudeDelta=0.01;
span.longitudeDelta=0.01;
region.span=span;
[mapView setRegion:region animated:TRUE];
}
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我可以在第二种方法中设置断点,NSLog报告连续的位置更新,但由于某种原因,带有span的缩放不起作用.知道为什么吗?它有我的坐标和一切.在这一个上刮我的头.
我有两个数组,我正在比较[Int]
let filter = strongAgainstArray.filter{weakAgainstArray.contains($0)}
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这将返回2个数组中的公共值数组.然后我想通过并从每个数组中删除这些值,我正在这样做
for item in filter {
for var i = 0; i < strongAgainstArray.count; i += 1 {
if item == strongAgainstArray[i] {
strongAgainstArray.removeAtIndex(i)
print("Removing a Strong against index \(item)")
}
}
for var i = 0; i < weakAgainstArray.count; i += 1 {
if item == weakAgainstArray[i] {
weakAgainstArray.removeAtIndex(i)
print("Removing a Weak against index \(item)")
}
}
}
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这工作正常,但我们可以说我的一个数组包含两个条目12作为示例.我如何只删除其中一个?目前,所有条目12都被完全删除.
编辑
我现在正在比较我的两个数组
let commonValues = Array(Set(strongAgainstArray).intersect(weakAgainstArray))
然后是commonValues每个数组中的那些
cleanStrongAgainstArray = …Run Code Online (Sandbox Code Playgroud)