我有一个我计划用来登录的Bootstrap下拉菜单.它似乎很好,但是当我选择用户名nput时它会消失,因为焦点已经转移到输入.我将如何添加对输入的支持,或者是否有一种工作方法?
我目前的代码是:
<li id="fat-menu" class="dropdown">
<a href="#" id="drop3" role="button" class="dropdown-toggle" data-toggle="dropdown" data-target="#">Login <b class="caret"></b></a>
<ul class="dropdown-menu" role="menu" aria-labelledby="drop3">
<li role="presentation"><input name="username" type="text" placeholder="Username" /></li>
<li role="presentation"><input name="password" type="password" placeholder="Password" /></li>
<li role="presentation" class="divider"></li>
<li role="presentation"><a role="menuitem" tabindex="-1" href="#">Login</a></li>
</ul>
</li>
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我尝试jsfiddle.我根本无法获得下拉列表:http://jsfiddle.net/KF8dv/
当我第一次开始播放AUGraph并播放带有kAudioUnitSubType_AudioFilePlayer
组件的歌曲时,我收到了一个声音.口吃约3秒,但它足以打扰我加上我注意到音乐在播放时有时会停止一瞬间(我猜缓冲?).我已经尝试kAudioUnitProperty_ScheduledFilePrime
将更改为随机值但注意没有变化.
我应该改变哪些变量或值来摆脱这个缺陷?这是流格式的问题吗?
我正在使用来自https://github.com/ronaldmannak/YBAudioFramework/tree/master/YBAudioUnit的YBAudioUnit
码:
YBAudioFilePlayer:
- (void)setFileURL:(NSURL *)fileURL typeHint:(AudioFileTypeID)typeHint {
if (_fileURL) {
// Release old file:
AudioFileClose(_audioFileID);
}
_fileURL = fileURL;
if (_fileURL) {
YBAudioThrowIfErr(AudioFileOpenURL((__bridge CFURLRef)fileURL, kAudioFileReadPermission, typeHint, &_audioFileID));
YBAudioThrowIfErr(AudioUnitSetProperty(_auAudioUnit, kAudioUnitProperty_ScheduledFileIDs, kAudioUnitScope_Global, 0, &_audioFileID, sizeof(AudioFileID)));
// Get number of audio packets in the file:
UInt32 propsize = sizeof(_filePacketsCount);
YBAudioThrowIfErr(AudioFileGetProperty(_audioFileID, kAudioFilePropertyAudioDataPacketCount, &propsize, &_filePacketsCount));
// Get file's asbd:
propsize = sizeof(_fileASBD);
YBAudioThrowIfErr(AudioFileGetProperty(_audioFileID, kAudioFilePropertyDataFormat, &propsize, &_fileASBD));
// Get unit's asbd:
propsize = sizeof(_fileASBD);
AudioUnitGetProperty(_auAudioUnit, kAudioUnitProperty_StreamFormat, kAudioUnitScope_Output, …
Run Code Online (Sandbox Code Playgroud) 我有一个在NSLog中输出的数组:
log: (
{
"case_color" = White;
"case_description" = "";
"case_image" = "http://site.com/get/parts/part_images/nzxtphantom410.jpeg";
"case_name" = "NZXT Phantom 410";
"case_price" = "99.99";
"case_type" = ATX;
id = 1;
}
)
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我怎么能把它放在一个NSDictionary中,所以我可以这样称呼:
NSDictionary *object;
NSString *casename object[@"case_name"];
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和casename等于"NZXT Phantom 410"
我在使用此查询时遇到问题,该查询会根据不同表中的回复数量对论坛主题进行排序.我尝试使用左连接之前的地方,但我的while循环中遗漏了一些数据.
SELECT forum_topics.*, COUNT(forum_posts.comment_id) AS replies
FROM forum_topics
WHERE forum_topics.subcat_id = '$subcatid'
LEFT JOIN forum_posts
ON forum_topics.topic_id=forum_posts.topic_num
ORDER BY replies DESC
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它给我这个错误:
You have an error in your SQL syntax; check the manual that corresponds to your
MySQL server version for the right syntax to use near 'LEFT JOIN forum_posts ON
forum_topics.topic_id=forum_posts.topic_num ORDER BY r' at line 1
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这是之前正在运行的查询:
SELECT * FROM forum_topics WHERE subcat_id = '$subcatid' ORDER BY date DESC
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为了回应我使用:
$getChildCategory = mysql_query($query) or die(mysql_error());
$num = mysql_num_rows($get); …
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