小编use*_*995的帖子

我正在通过JSON提取twitter用户的个人资料图片.为此,我的代码是:

$x->profile_image_url

返回配置文件图像的URL.URL的格式可以是"..xyz_normal.jpg"或"..xyz_normal.png"或"..xyz_normal.jpeg"或"..xyz_normal.gif"等

现在我想从我收到的每个网址中删除"_normal"部分.我怎么能在PHP中实现这一点？我已经厌倦了尝试.请帮忙.

我正在尝试将一个非常大的输入读取为String,然后将其转换long为如下所示:[该程序适用于短输入]

输入是两个int用空格分隔的,例如:"1248614876148768372675689568324619856329856295619253291561358926935829358293587932857923857934572895729511 413241"

我的代码:

import java.io.*;
import java.math.*;
import java.util.*;
public class Solution {
    public static void main(String args[] ) throws Exception {
        Solution obj = new Solution();
        BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
        int T = Integer.parseInt(br.readLine());
        String input[]=new String[T];
        for (int i=0;i<T;i++) {
            input[i] = br.readLine();
            }
        for (int i=0;i<T;i++){
            StringTokenizer st = new StringTokenizer(input[i]," ");
                BigInteger N = new BigInteger(st.nextToken());
                BigInteger P = new BigInteger(st.nextToken());
                System.out.println(obj.result(N,P));
            }
        }
    }

    public BigInteger result(BigInteger …