我正在尝试使用wamp创建一个新的zend项目.
Microsoft Windows XP [Version 5.1.2600]
(C) Copyright 1985-2001 Microsoft Corp.
C:\> cd wamp\www\zendtest*
C:\wamp\www\zendtest>C:\wamp\www\zend\bin\zf.bat create project quickstart*
'"php.exe"' is not recognized as an internal or external command,
operable program or batch file.
C:\wamp\www\zendtest>
Run Code Online (Sandbox Code Playgroud)
我的环境变量路径是
%SystemRoot%\ system32;%SystemRoot%;%SystemRoot%\ System32\Wbem; C:\ PROGRA~1\IBM\SQLLIB\BIN; C:\ PROGRA~1\IBM\SQLLIB\FUNCTION; C:\ Program Files \的Zend\MySQL51\BIN; C:\瓦帕\ WWW\Zend的\ BIN;
哪个部分我认为是错误的.