我使用以下jQuery语句,我收到错误,
jQuery.parseJSON不是一个函数
我的功能是,
function Iteratejsondata() {var HfJsonValue =
{ "Table": [{ "Emp_Id": "3",
"Identity_No": "",
"Emp_Name": "Jerome",
"Address": "Madurai",
"Date_Of_Birth": "",
"Desig_Name": "Supervisior",
"Desig_Description": "Supervisior of the Construction",
"SalaryBasis": "Monthly",
"FixedSalary": "25000.00" },
{ "Emp_Id": "4",
"Identity_No": "",
"Emp_Name": "Mohan",
"Address": "Madurai",
"Date_Of_Birth": "",
"Desig_Name": "Acc ",
"Desig_Description": "Accountant",
"SalaryBasis": "Monthly",
"FixedSalary": "200.00" },
{ "Emp_Id": "5",
"Identity_No": "",
"Emp_Name": "Murugan",
"Address": "Madurai",
"Date_Of_Birth": "",
"Desig_Name": "Mason",
"Desig_Description": "Mason",
"SalaryBasis": "Weekly",
"FixedSalary": "150.00" },
{ "Emp_Id": "6",
"Identity_No": "",
"Emp_Name": …Run Code Online (Sandbox Code Playgroud) Hai Guys,我想将光标设置在文本框上长度为14的位置,该文本框没有值..我知道最初光标将为0我希望它在14
我有一个函数,它根据输入字符串选择文本.如果两个匹配我选择它.PFb的功能,
function setDropdownTextContains(dropdownId,selectedValue,hfId){
$('#'+dropdownId+' option').each(function(){
if($(this).text() === selectedValue){
$(this).attr("selected", "selected");
break;
}
});
$('#'+hfId).val("ModelName doesnt match");
}
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我得到以下错误unlabeled break must be inside loop or switch......我做错了什么?
我在stackoverflow中问这个问题,因为它是正确的地方......
我知道这是一个非常广泛的话题,但是一些可能非常方便的小话题......
像我这样的年轻开发人员可能对查询优化有所了解.
有关SQL Server 2005中查询优化的一些提示和技巧 ..
在使用我的一个asp.net Web应用程序与WCF合作之后,我真的很喜欢ajax的东西与我的应用程序一起工作的方式......
关于来自专家的WCF的一些有用的提示和技巧对我这样的初学者来说真的很有用......任何有用的提示和技巧....
基于StackOverflow 上的Memory Efficient Programming问题.....我想了解Memory Efficient C#Programming ....任何关于Memory Efficient C#编程的好网站/博客/书籍......
编辑:
一些提示如何编写内存高效的C#编程....
重复:
我的JSON数据看起来像这样
{
"Table": [{
"Emp_Id": "3",
"Identity_No": "",
"Emp_Name": "Jerome",
"Address": "Madurai",
"Date_Of_Birth": "",
"Desig_Name": "Supervisior",
"Desig_Description": "Supervisior of the Construction",
"SalaryBasis": "Monthly",
"FixedSalary": "25000.00"
}, {
"Emp_Id": "4",
"Identity_No": "",
"Emp_Name": "Mohan",
"Address": "Madurai",
"Date_Of_Birth": "",
"Desig_Name": "Acc ",
"Desig_Description": "Accountant",
"SalaryBasis": "Monthly",
"FixedSalary": "200.00"
}, {
"Emp_Id": "5",
"Identity_No": "",
"Emp_Name": "Murugan",
"Address": "Madurai",
"Date_Of_Birth": "",
"Desig_Name": "Mason",
"Desig_Description": "Mason",
"SalaryBasis": "Weekly",
"FixedSalary": "150.00"
}, {
"Emp_Id": "6",
"Identity_No": "",
"Emp_Name": "Ram",
"Address": "Madurai",
"Date_Of_Birth": …Run Code Online (Sandbox Code Playgroud) 我在我的一个create.aspx中使用了一个下拉列表,但它有些似乎无法正常工作......
public IEnumerable<SelectListItem> FindAllMeasurements()
{
var mesurements = from mt in db.MeasurementTypes
select new SelectListItem
{
Value = mt.Id.ToString(),
Text= mt.Name
};
return mesurements;
}
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和我的控制器,
public ActionResult Create()
{
var mesurementTypes = consRepository.FindAllMeasurements().AsEnumerable();
ViewData["MeasurementType"] = new SelectList(mesurementTypes,"Id","Name");
return View();
}
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我的create.aspx有这个,
<p>
<label for="MeasurementTypeId">MeasurementType:</label>
<%= Html.DropDownList("MeasurementType")%>
<%= Html.ValidationMessage("MeasurementTypeId", "*") %>
</p>
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当我执行这个我得到这些错误,
DataBinding: 'System.Web.Mvc.SelectListItem' does not contain a
property with the name 'Id'.
Run Code Online (Sandbox Code Playgroud) 将此视为我的json字符串,
{"Table" : [{"userid" : "11","name" : "KumarP","designation" : "Business Head",
"phone" : "9789234793","email" : "surfingkumar@gmail.com","role" : "Admin",
"empId" : "EI003","reportingto" : "KumarP"}]}
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我希望我的字符串像这样,
{Table:[{ userid: "11", name: "KumarP", designation: "Business Head",
phone: "9789234793", email:"surfingkumar@gmail.com", role : "Admin",
empId : "EI003",reportingto : "KumarP"}]}
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我这样做是为了与jlinq一起使用..
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