小编AKH*_*and的帖子

我正在运行其网站中提到的这个kafka生产者示例

代码:

public class TestProducer {

    public static void main(String[] args) {
        long events = Long.parseLong(args[0]);
        Random rnd = new Random();
        Properties props = new Properties();
        props.put("metadata.broker.list", "host.broker-1:9093, host.broker-2:9093, host.broker-3:9095");
        props.put("serializer.class", "kafka.serializer.StringEncoder");
        props.put("partitioner.class", "test.app.SimplePartitioner");
        props.put("request.required.acks", "1");
        ProducerConfig config = new ProducerConfig(props);
        Producer<String, String> producer = new Producer<String, String>(config);
        for (long nEvents = 0; nEvents < events; nEvents++) { 
               long runtime = new Date().getTime();  
               String ip = "192.168.2." + rnd.nextInt(255); 
               String msg = runtime + ",www.example.com," + ip; 
               KeyedMessage<String, String> data …

嗨我有一个问题,在iOS8中旋转Modal呈现的ViewController.这一切在iOS7及更低版本上运行良好.

应用结构:

• RootController(支持的Orientation:Portrait)
• Modal提供的ViewController(支持的Orientation:All)

我的问题是当我提出模态控制器时旋转设备时,模态控制器的视图没有调整到景观框架.

看起来像这样:

调用了旋转方法,当我手动将视图的框架设置为横向时,右侧(屏幕灰色侧)的用户交互不起作用.

RootController代码:

- (UIInterfaceOrientation)preferredInterfaceOrientationForPresentation
{
    return UIInterfaceOrientationPortrait;
}

- (NSUInteger) supportedInterfaceOrientations
{
    return UIInterfaceOrientationMaskPortrait;
}

模态控制器代码:

- (NSUInteger)supportedInterfaceOrientations
{
    return UIInterfaceOrientationMaskAll;
}


- (void)willAnimateRotationToInterfaceOrientation:(UIInterfaceOrientation)toInterfaceOrientation
                                         duration:(NSTimeInterval)duration
{
    if (self.presentingViewController != nil) {
        [self.presentingViewController willAnimateRotationToInterfaceOrientation:toInterfaceOrientation
                                                                        duration:duration];
    }
}

- (void)willRotateToInterfaceOrientation:(UIInterfaceOrientation)toInterfaceOrientation
                                duration:(NSTimeInterval)duration
{
    if (self.presentingViewController != nil) {
        [self.presentingViewController willRotateToInterfaceOrientation:toInterfaceOrientation
                                                               duration:duration];
    }
}

- (void)didRotateFromInterfaceOrientation:(UIInterfaceOrientation)fromInterfaceOrientation
{
    if (self.presentingViewController != nil) {
        [self.presentingViewController didRotateFromInterfaceOrientation:fromInterfaceOrientation];
    }
}

- (void)viewWillTransitionToSize:(CGSize)size withTransitionCoordinator:(id<UIViewControllerTransitionCoordinator>)coordinator
{
    [super viewWillTransitionToSize:size withTransitionCoordinator:coordinator];

    [coordinator animateAlongsideTransition:^(id<UIViewControllerTransitionCoordinatorContext> context) {

    } …

我有这两个代码片段似乎应该产生相同的结果,但后者导致错误.

1:

my $href = undef;
my @values = values %{ $href };
# OK - @values is empty

2:

my $href = undef;
my %hash = %{ $href }; # <-- Error here
my @values = values %hash;
# ERROR: Can't use an undefined value as a HASH reference

为什么values在同一行中允许它工作？我宁愿他们都抛出错误,因为使用未定义的值作为哈希引用显然是一个错误.我没有更新的perl版本可供测试,但这在5.8.8和5.10.1中是可重现的.

所以,我只是追踪了一个可以在这个简单的子程序中演示的错误:

sub foo {
    my $bar = shift or die "Missing bar", # <--- not a semicolon
    my @items = ();
    push @items, $bar;
    return @items;
}

显然,错误是子程序的第一行以逗号结尾.这有一些相当不寻常的后果,可以看出:

say foo(1); # 1
say foo(1); # 11
say foo(1); # 111
say foo(1); # 1111

现在,我知道这不是语法错误,因为逗号运算符的工作原理.据我所知,@items没有设定,()因为or没有达到右侧.我的问题是,如何my在子程序内部声明的变量允许数据在子程序调用之间持续存在？看起来好像my变成了our某种程度.

Jquery是否有更简单/更短的方式来编写这样的if语句:

if(number === "0" ) { degrees = "-160"; }
if(number === "1" ) { degrees = "-158"; }
if(number === "2" ) { degrees = "-156"; }
if(number === "3" ) { degrees = "-154"; }
if(number === "4" ) { degrees = "-152"; }
if(number === "5" ) { degrees = "-150"; }
if(number === "6" ) { degrees = "-148"; }
if(number === "7" ) { degrees = "-146"; }
if(number === "8" ) { degrees = …

我想分割字符串中的每个字符并将其输出为逗号或制表符分隔字符：我需要使用file_inandfile_out因为我有很多行。

输入

TTTGGC
TTTG
TGCAATGG
....
....

输出

T,T,T,G,G,C
T,T,T,G
T,G,C,A,A,T,G,G

我已经使用过这个，但它垂直打印每个字符：

  /usr/bin/perl
   use strict;
   use warnings;

    my $data = 'Becky Alcorn';

   my @values = split(undef,$data);

  foreach my $val (@values) {
   print "$val\n";
  }

  exit 0;

1064:You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near ''models'( 'model_id' INT NOT NULL AUTO_INCREMENT PRIMARY KEY, 'model_usernam' at line 1

我尝试创建sql表时出现此错误.

这是代码..请帮忙..

$sql = "CREATE TABLE IF NOT EXISTS 'models'(
    'model_id' INT NOT NULL AUTO_INCREMENT PRIMARY KEY,
    'model_username' VARCHAR(250) NOT NULL,
    'model_gender' ENUM('f','m','s','c') NOT NULL,
    'model_show' ENUM('public','private','group','away') NOT NULL,
    'model_age' INT NOT NULL,
    'model_time' INT NOT NULL,
    'model_new' TINYINT(1) NOT NULL default '0', …