小编use*_*681的帖子

如何计算递归函数中的案例数?

def calcPath(trace_map, x, y):
    n = len(trace_map)
    count = 0
    if x > n - 1 or y > n - 1:
        pass
    elif x < n and y < n:
        if x + trace_map[x][y] == (n - 1) and y == (n - 1):
            count += 1
        elif x == (n - 1) and y + trace_map[x][y] == (n - 1):
            count += 1
        else:
            calcPath(trace_map, x + trace_map[x][y], y)
            calcPath(trace_map, x, y + trace_map[x][y])
    return count


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python recursion counter if-statement counting

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推荐指数
1
解决办法
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counter ×1

counting ×1

if-statement ×1

python ×1

recursion ×1