小编cod*_*c24的帖子

我在一个文件中有数据，其中一列是日期列，其日期格式如下：

2021-05-10T18:25:00.000+0100
2021-05-14T18:25:00.000+0100
2021-05-19T18:25:00.000+0100

预期输出为：

10 MAY 2021
14 MAY 2021
19 MAY 2021

我尝试过的方法：

while -r read line
do
    year=`echo $line | awk '{ print $1 }' `
    month=`echo $line | awk '{ print $2 }' `
    dt=`echo $line | awk '{ print $3 }' `

    v=$dt"-"$month"-"$year
    d=date '`$v' | dd-mm-yyyy
    echo $d
done < /f/filename.txt

我的文件中没有任何数据 需要检查以下场景并返回文件为空，否则不为空

if file contains no data but as only spaces return it as FILE is EMPTY 
if file contains no data but as only tabs   return it as FILE is EMPTY
if file contains no data but as only empty new line  return it as FILE is EMPTY  

下面的代码是否能满足我上述所有情况？或一次性使用任何最佳方法

if [ -s /d/dem.txt ]
then
    echo "FILE IS NOT EMPTY AS SOME DATA"
else
    echo "FILE IS EMPTY NOT DATA AVAILABLE"
fi