小编Sea*_*n F的帖子

到目前为止,谢谢你的帮助,我正在更新问题,因为我没有显示我需要的所有内容,显示的更改显示.肥皂输出仍然不是我想要的.

servlet.xml中

<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
    xmlns:context="http://www.springframework.org/schema/context"
    xmlns:p="http://www.springframework.org/schema/p"
    xmlns:sws="http://www.springframework.org/schema/web-services"
    xmlns:oxm="http://www.springframework.org/schema/oxm"
    xsi:schemaLocation="http://www.springframework.org/schema/beans
                        http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
                        http://www.springframework.org/schema/web-services
                        http://www.springframework.org/schema/web-services/web-services-2.0.xsd
                        http://www.springframework.org/schema/context 
                        http://www.springframework.org/schema/context/spring-context-3.0.xsd
                        http://www.springframework.org/schema/oxm 
                        http://www.springframework.org/schema/oxm/spring-oxm-3.0.xsd"
                        >

<!--Enables @Endpoint and related Spring-WS annotations.-->
<sws:annotation-driven marshaller="marshaller" unmarshaller="marshaller"/> 

<bean id="weatherService"
    class="au.test.weather.ws.WeatherServiceImpl" />

<bean id="schema" class="org.springframework.xml.xsd.SimpleXsdSchema" 
    p:xsd = "classpath:au/test/weather/ws/schemas/Temperature.xsd"/>

<oxm:jaxb2-marshaller id="marshaller" >
    <oxm:class-to-be-bound name="au.test.weather.ws.GetTemperaturesResponse"/> 
    <oxm:class-to-be-bound name="au.test.weather.ws.GetTemperaturesRequest"/>
    <oxm:class-to-be-bound name="au.test.weather.ws.schemas.Jaxb2Marshaller"/>  
</oxm:jaxb2-marshaller> 

<bean id="temperatureEndpoint"
    class="au.test.weather.ws.TemperatureMarshallingEndpoint">
    <property name="weatherService" ref="weatherService" />
</bean>

我的注释类看起来像什么

@XmlRootElement(name = "GetTemperaturesRequest")
public class GetTemperaturesRequest {

    @XmlElement(required = true)
    protected String city;
    @XmlElement(required = true)
    @XmlSchemaType(name = "date")
    protected List<XMLGregorianCalendar> …

让我们说我上课了

@XmlType(propOrder = {
        "one",
        "two"
    })

@XmlRootElement(name = "search")
public class Search {

    protected One one;  
    protected Two two;

    //getters & setters
}

我想要一个扩展这个类的类

例如

@XmlType(propOrder = {
        "three"
    })

@XmlRootElement(name = "searchExtended")
public class SearchExtended extends Search {

    protected Three three;  
    //getters & setters
}

你如何正确地声明propOrder,我之前尝试了这个,它没有使用我认为它会的顺序.这是如何通过注释处理的？/你应该如何在扩展类中声明这一点？

我有这个错误,它说我有两个相同的XML类型名称类

所以问题出在InfoSource - > NameSearchFilters - > SearchRequest之间

错误

Caused by: com.sun.xml.internal.bind.v2.runtime.IllegalAnnotationsException: 2 counts of IllegalAnnotationExceptions
Two classes have the same XML type name "{http://test.au/schema/namesearch}InfoSource". Use @XmlType.name and @XmlType.namespace to assign different names to them.
    this problem is related to the following location:
        at au.test.identitySearch.model.InfoSource
        at protected au.test.identitySearch.model.InfoSource au.test.identitySearch.model.nameSearch.NameSearchFilters.infoSourceList
        at au.test.identitySearch.model.nameSearch.NameSearchFilters
    this problem is related to the following location:
        at au.test.identitySearch.model.InfoSource
        at protected au.test.identitySearch.model.InfoSource au.test.identitySearch.model.nameSearch.NameSearchFilters.infoSourceList
        at au.test.identitySearch.model.nameSearch.NameSearchFilters
        at protected au.test.identitySearch.model.nameSearch.NameSearchFilters au.test.identitySearch.ws.model.SearchRequest.searchFilters
        at au.test.identitySearch.ws.model.SearchRequest

InfoSource

@XmlAccessorType(XmlAccessType.FIELD)
@XmlType(name = "InfoSource", propOrder = …

我尝试在Java中使用Math.reverseBytes但是给出错误:方法reverseBytes()未定义为Math类型

如你所知它是静态类型.为什么我不能使用它？

import java.lang.Integer;

public class Test {
    public static void main(String[] args) {
        int x = Math.reverseBytes();//Eclipse cannot reach this function
    }
}

来自Java Doc - 一些信息

reverseBytes

public static int reverseBytes(int i);

返回通过反转指定int值的二进制补码表示中的字节顺序获得的值.

返回:通过反转指定int值中的字节获得的值.

自:1.5