小编geo*_*dex的帖子

如何在R中的嵌套列表中删除以下data.frames列的属性？

List of 1
 $ 0021400001:List of 19
   $ GameSummary      :'data.frame':    1 obs. of  13 variables:
    $ GAME_DATE_EST                   : Factor w/ 1 level "2014-11-09T00:00:00": 1
      - attr(*, "names")= chr "1"
    $ GAME_SEQUENCE                   : Factor w/ 1 level "2": 1
      - attr(*, "names")= chr "2"
    $ GAME_ID                         : Factor w/ 1 level "0021400091": 1
      - attr(*, "names")= chr "3"
    $ GAME_STATUS_ID                  : Factor w/ 1 level "3": 1
      - attr(*, "names")= chr "4" 
   $ SeasonSeries     :'data.frame':    1 obs. of  7 variables: …

如何使用复选框从数据框或表中选择数据行？我已经完成了以下代码,但似乎复选框项目是列,并没有真正显示结果.

谢谢你的帮助.

server.R

   shinyServer(function(input, output) {
       dataset<-reactive({
         data(cars)
         cars
       })

       output$choose_data <- renderUI({
         checkboxGroupInput("dtab", "Data Table", dataset()) 
    })

       dataset2<-reactive({
         input$dtab         
    })      

       output$data_table <- renderTable({
         data2()                    
       })
    })

ui.R

   shinyUI(pageWithSidebar(
         headerPanel(""),

         sidebarPanel(
         uiOutput("choose_data"),
         br()
         ),

        mainPanel(
        wellPanel("Data", tableOutput("data_table")
    ))))

我有以下数据框p3:

         test     result
    1      1    26.87778
    2      1    24.52598
    3      1    24.02202
    4      1    20.32632
    5      1    22.00618
    6      2    19.84013
    7      2    19.68983
    8      2    19.84013
    9      2    19.23892
    10     2    19.23892
    11     3    34.36430
    12     3    33.28196
    13     3    33.82313
    14     3    33.82313
    15     3    32.47020
    16     4    25.55169
    17     4    26.90442
    18     4    25.40138
    19     4    24.19895
    20     4    25.85230
    21     4    25.70199
    22     4    24.95047
    23     5    18.64646
    24     5    18.64646
    25     5    17.80653
    26     5 …

我有以下data.frame

df = structure(list(HEADER = c("HOME_TRPM", "AWAY_TRPM", "HOME_TEAM","AWAY_TEAM"),
                     price = c("0.863104076023855", "-0.845186446996287","CHA", "NOP")),
               .Names = c("HEADER", "price"), row.names = c(NA, 4L), class = "data.frame")

df
#>      HEADER              price
#> 1 HOME_TRPM  0.863104076023855
#> 2 AWAY_TRPM -0.845186446996287
#> 3 HOME_TEAM                CHA
#> 4 AWAY_TEAM                NOP

我想要转置.如何在不使用t()的情况下在dplyr中执行此操作？我试过了

df %>% tidyr::spread(HEADER , price)

但它不会给出扁平结构,而是这样做:

structure(list(AWAY_TEAM = c(NA, NA, NA, "NOP"),
     AWAY_TRPM = c(NA, "-0.845186446996287", NA, NA), 
     HOME_TEAM = c(NA, NA, "CHA", NA),
     HOME_TRPM = c("0.863104076023855", NA, NA, NA)),
 .Names = c("AWAY_TEAM", "AWAY_TRPM", "HOME_TEAM", …

我有以下数据

GT-BU7867-09
GT-BU6523-113
GT-BU6452-1
GT-BU8921-12

如何使用R来使连字符后面的数字填充前导零,以便它有三位数？生成的格式应如下所示:

GT-BU7867-009
GT-BU6523-113
GT-BU6452-001
GT-BU8921-012

我有以下数据作为示例:

 basketball = c("MISS W. Johnson 18' Pullup Jump Shot",
                "MISS Barnes 12' Pullup Jump Shot",
                "MISS Carter  19' Pullup Jump Shot")

我如何找到最常见的单词或"相交"它们,以便我只能得到"MISS Pullup Jump Shot"结果？

如何在Perl中获取对象的数据结构？

我可以使用str轻松地在R中执行此操作

    str(data)

我想知道Perl中是否有类似的.

如何合并data.frames中的data.frame和重叠间隔？

数据框1

read.table(textConnection(
 "   from to Lith Form 
1   0   1.2 GRN   BCM
2   1.2 5.0 GDI   BDI
"), header=TRUE)    

数据框2

read.table(textConnection(
"   from to Weath Str
1   0  1.1  HW ES
2   1.1 2.9 SW VS
3   2.9 5.0 HW ST 
"), header=TRUE) 

产生的数据框架

from to Weath Str Lith Form
1 0.0 1.1 HW ES GRN  BCM
2 1.1 1.2 SW VS GRN  BCM
3 1.2 2.9 SW VS GDI  BDI
4 2.9 5.0 HW ST GDI  BDI

如何根据间隔剪切两个数据帧并合并它们？

数据框1

read.table(textConnection(
"   from to Lith  
1   0   1.2 GRN   
2   1.2 5.0 GDI   
"), header=TRUE)    

数据框2

read.table(textConnection(
"   from to Weath  
1   0  1.1  HW  
2   1.1 2.9 SW 
3   2.9 5.0 HW  
"), header=TRUE) 

产生的数据框架

  from to Weath Lith 
1 0.0 1.1 HW  GRN
2 1.1 1.2 SW  GRN
3 1.2 2.9 SW  GDI
4 2.9 5.0 HW  GDI