小编use*_*221的帖子

我使用textFields inputView属性来显示UIPickerViews而不是键盘.我编程的方式,我没有在.H文件中声明PickerViews,或者在界面构建器的视图中连接它们.当我实现pickerviews的属性时,我无法使每个属性具有不同的属性.我尝试使用"if"语句告诉它具有不同的属性,具体取决于使用的选择器如下....

-(NSInteger)numberOfComponentsInPickerView:(UIPickerView *)agePickerView {
    if ([pickerView isEqual: agePickerView]){
                 return 1;
    }
            if ([pickerView isEqual: weightPickerView]){
                 return 1;
    }

}

当我这样做时,它会说weightPickerView是未声明的.所以这是我实现pickerViews的代码.

@implementation MainViewController

//WEIGHT FIELD CODE 

-(IBAction)weightFieldDidBeginEditing{
UIPickerView *weightPickerView = [[UIPickerView alloc] init];
weightField.inputView = weightPickerView;
weightPickerView.showsSelectionIndicator = YES;
weightPickerView.delegate = self;
weightPickerView.dataSource = self;
[weightPickerView release];

UIToolbar *weightToolBar = [[UIToolbar alloc] initWithFrame:CGRectMake(0,0,320,44)];
UIBarButtonItem *doneButton = [[UIBarButtonItem alloc]   initWithBarButtonSystemItem:UIBarButtonSystemItemDone target:self action:@selector(pickerDoneClicked:)];
[weightToolBar setItems:[NSArray arrayWithObject:doneButton] animated:NO];
 weightField.inputAccessoryView = weightToolBar;
}

-(NSInteger)weightpickerView:(UIPickerView *)weightPickerView numberOfRowsInComponent: (NSInteger)component{
return [weightPickerArray count];
}

-(NSString *)weightpickerView:(UIPickerView*)weightPickerView titleForRow:(NSInteger)row …