我想在我的Android浏览器中检查我的网站CSS/HTML元素.
但它将通过智能手机或Android SDK.
最好的方法是什么?
我希望css.css覆盖所有的类,标签和ID bootstrap.min.css 而不重复类,标签和ID bootstrap.min.css.
<link href="css/bootstrap.min.css" rel="stylesheet">
<link href="css/css.css" rel="stylesheet">
Run Code Online (Sandbox Code Playgroud) 我正在尝试添加phpmyadmin到Laravel 8 docker-compose.yml文件。
现在,我可以phpmyadmin在“http://localhost:8080”上访问,但没有用户无法登录:
Cannot log in to the MySQL server
mysqli::real_connect(): php_network_getaddresses: getaddrinfo failed: Name or service not known
mysqli::real_connect(): (HY000/2002): php_network_getaddresses: getaddrinfo failed: Name or service not known
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我的docker-compose.yml文件看起来像这样:
# For more information: https://laravel.com/docs/sail
version: "3"
services:
laravel.test:
build:
context: ./vendor/laravel/sail/runtimes/8.0
dockerfile: Dockerfile
args:
WWWGROUP: "${WWWGROUP}"
image: sail-8.0/app
ports:
- "${APP_PORT:-80}:80"
environment:
WWWUSER: "${WWWUSER}"
LARAVEL_SAIL: 1
volumes:
- ".:/var/www/html"
networks:
- sail
depends_on:
- mysql
# - pgsql …Run Code Online (Sandbox Code Playgroud) 我使用joomla 2.5,我想创建一个自定义表单字段类型 that stored in the same module.
在XML中:
<fieldset name="basic" addfieldpath="/modules/mod_royalslider/fields"></fields>
<fieldset name="basic">
<field name="title" type="City" label="anythging" description="" />
</fieldset>
</fields>
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在文件中 /modules/mod_royalslider/fields/city.php
<?php
// Check to ensure this file is included in Joomla!
defined('_JEXEC') or die('Restricted access');
jimport('joomla.form.formfield');
class JFormFieldCity extends JFormField {
protected $type = 'City';
// getLabel() left out
public function getInput() {
return '<select id="'.$this->id.'" name="'.$this->name.'">'.
'<option value="1" >New York</option>'.
'<option value="2" >Chicago</option>'.
'<option value="3" >San Francisco</option>'.
'</select>';
}
}
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现在它显示我的错误,当我删除
<fieldset name="basic" addfieldpath="/modules/mod_royalslider/fields"></fields>
错误消失,字段显示为文本字段.
我创建了这个功能,可以在许多应用程序上很好地共享图像,但当涉及到WhatsApp或 Instagram 时,它无法共享图像。
async shareImage() {
let receiptName = 'Receipt N:123.png';
const div = this.screenshotElement.nativeElement;
const divHeight = div.clientHeight;
const divWidth = div.clientWidth;
const options = { background: '#ffffff', width: divWidth, height: divHeight };
await Filesystem.requestPermissions();
let base64Data = await domtoimage.toPng(div, options);
// device shareing
await Filesystem.writeFile({
path: receiptName,
data: base64Data,
directory: Directory.Cache
});
let fileResult = await Filesystem.getUri({
directory: Directory.Cache,
path: receiptName
});
let imageLink = Capacitor.convertFileSrc(fileResult.uri);
Share.share({
title: receiptName,
text: receiptName, …Run Code Online (Sandbox Code Playgroud) ErrorException Array to string conversion当我运行播种器时出现错误。
php artisan db:seed --class=StudentSeeder
在我对 进行更改之前它工作得很好StudentFactory.php,我只是更改了所有的伪造者,而且我不知道是哪个伪造者造成了这个麻烦。
<?php\n\nnamespace Database\\Factories;\n\nuse Illuminate\\Database\\Eloquent\\Factories\\Factory;\nuse Illuminate\\Support\\Str;\nuse App\\Models\\Student;\n\nclass StudentFactory extends Factory\n{\n /**\n * The name of the factory's corresponding model.\n *\n * @var string\n */\n protected $model = Student::class;\n\n /**\n * Define the model's default state.\n *\n * @return array\n */\n public function definition()\n {\n return [\n 'student_name' => $this->faker->name('male'),\n 'cpr' => $this->faker->creditCardNumber,\n 'email' => $this->faker->safeEmail,\n 'mobile' => $this->faker->e164PhoneNumber,\n 'mobile2' => $this->faker->e164PhoneNumber,\n 'dob' => $this->faker->date(),\n 'address' …Run Code Online (Sandbox Code Playgroud)