我有:
$scope.bounds = {}
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后来在我的代码中:
$scope.$on('leafletDirectiveMap.load', function(){
console.log('runs');
Dajaxice.async.hello($scope.populate, {
'west' : $scope.bounds.southWest.lng,
'east': $scope.bounds.northEast.lng,
'north' : $scope.bounds.northEast.lat,
'south': $scope.bounds.southWest.lat,
});
});
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你可以在乞讨中看到它们是空的边界但是它们稍后(几毫秒)用一个javascript库(小叶角度)加载.但是,$scope.$on(...)设置了边界之前的运行,因此'west' : $scope.bounds.southWest.lng,返回带有未定义变量的错误.
我想要做的是等待边界(southWest和northEast)设置然后运行Dajaxice.async.hello(...).
所以我需要"等到边界设置"之类的东西.
<parent v-on:click="isActive = !isActive">
<router-link :to="{ name: 'home'}">{{tag}}</router-link>
</parent>
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如果在父级中router-link单击 ,v-on:click仍将捕获该事件。
如何让router-link点击事件完全消费?
我试图给了一个弹出式鼠标悬停事件,而不是点击上的标记,并做一些一些其他的东西(如FUNC)我们得到点击的时候.
我不相信的一半成功的代码会帮助你思考这个方向:
(我只是在点击事件上添加悬停)
marker[i].on('mouseover', marker[i].bindPopup('hi').openPopup.bind(marker[i]));
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[i]只是代表一个循环
Leaflet的API:http://leaflet.cloudmade.com/reference.html#map-openpopup
我从两个列的mysql加载我的数据:id,rt
id对应于实践中的许多rts(我设计得很差的表):
id rt
1 5129052 2
2 5129052 2
3 5129052 5
4 5129052 6
5 7125052 0
6 7125052 1
7 7125052 2
8 7125052 4
9 7125052 6
10 7125052 7
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我想创建一个像下面那样的数据透视表.第一列只是行数,没什么特别的.
5129052 7125052
1 2 0
2 2 1
3 5 2
4 6 4
5 NA 6
6 NA 7
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如果可能,还会按升序对值进行排序.
谢谢!
csv的第一行有标题.这是我的csv的示例行:
2013-07-31 00:00:00,,1.0,2013.0,7.0,Q3,21160742,32HHBS1307170203,KL0602130731,AIRFRANCE
KLM,KLM,KLM,KLM,KL,KLM ROYAL DUTCH AIRLINES,,0602,,KL0602,KL,KLM ROYAL DUTCH
AIRLINES,,,,KL,0602,,,LAX,AMS,,31-7-2013 0:00:00,2013-07-31,2013-07-31,2013-07-31,2013-07-31,
13:55:00,14:39:00,20:55:00,21:39:00,2013-08-01,2013-08-01,2013-08-01,2013-08-01,
09:05:00,09:45:00,07:05:00,07:45:00,2.0,,2,,,LAX,LOS ANGELES INTERNATIONAL AIRPORT,
LAX,LAX,5.0,LAX,LOS ANGELES,US,UNITED STATES OF AMERICA,US,USA,NA8,NORTHERN AMERICA,
AMERICAS,,,,AMS,SCHIPHOL I,F,OFFLINE,I,INDIRECT OFFLINE,14.0,3.0,FRONT,Business,2.0,nan,
PLANNED,3.0,,2.0,2.0,34.0,4.0,400254887nan,1.0,2.0,2.0,2.0,1.0,2.0,6.0,3.0,1.0,3.0,1.0,1.0,
nan,nan,nan,nan,nan,nan,nan,3.0,3.0,3.0,nan,nan,nan,nan,nan,nan,nan,nan,nan,nan,nan,nan,nan,nan,
nan,2.0,2.0,2.0,2.0,2.0,7.0,nan,2.0,3.0,3.0,3.0,3.0,nan,nan,nan,nan,nan,nan,nan,nan,nan,
nan,nan,nan,nan,6.0,1.0,nan,nan,nan,nan,nan,2.0,nan,nan,nan,nan,nan,nan,nan,nan,nan,2.0,2.0,
nan,2.0,nan,3.0,nan,,nan,nan,nan,nan,nan,nan,nan,nan,nan,nan,nan,nan,nan,nan,nan,13.7885862654653,
0.2, 34273499844164,nan,37.0,Booked,35.0,10.0,2.0,2.0,6.0,35.0,10.0,42.0,nan,nan,LAX,LAX,N
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如果我使用两种input_file = csv.DictReader(open("file.csv")或者input_file = csv.reader(open('file.csv')),我的所有对象会变成字符串.
用python打印的一行:
'2013-08-31 00:00:00', '', '1.0', '2013.0', '8.0', 'Q3','C', '03J', '', '',
'', '', 'nan', 'nan', '', 'NON-AIRPORT', 'SELF-SERVICE', 'ICI', '', '19.0', '20130819',
'1.0', '19.0', '9.0', '20130901', '2.0', '1.0', '1.0', '1.0', '10.0', '5.0', '5.0', '3.0',
'4.0', '4.0', '2.0', '2.0', '', …Run Code Online (Sandbox Code Playgroud) 我使用了文档中的示例:
>>> Counter('abracadabra').most_common(3)
[('a', 5), ('r', 2), ('b', 2)]
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我怎样才能得到结果:
{ 'a': 5, 'r' :2 , 'b' :2}
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假设我们想保留Counter().most_common()代码?
这是我的代码:
LatLngBounds.Builder builder = new LatLngBounds.Builder();
for(int x = firstVisibleItem; x < lastVisibleItem; x++){
builder.include(temp.getPosition());
}
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但是这行引发了一个错误(java.lang.IllegalStateException: no included points
:
double north = builder.build().northeast.latitude;
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这是因为上面的循环根本没有运行所以没有包括在内builder.
如何检查构建器是否至少有一个点?
我尝试过builder.build()!=null抛出上面的错误,builder!=null并且始终为True.
try{}catch(IllegalStateException e){ } 作品.问一个!=null方法是愚蠢的吗?美高科技管理?谢谢
我一直在努力使用systrace.
我的设备运行4.1.2(LT28i),我在Mac上.我正在回答类似问题的SO问题,但没有一个人有明确的答案.
我想让我们说跟踪views和graphics
方法1,eclipse:

错误:

方法2,终端:
$ python systrace.py --cpu-load --time=10 -o mytracefile.html
error opening /sys/kernel/debug/tracing/options/overwrite: No such file or directory (2)
error opening /sys/kernel/debug/tracing/events/sched/sched_switch/enable: No such file or directory (2)
error opening /sys/kernel/debug/tracing/events/sched/sched_wakeup/enable: No such file or directory (2)
error opening /sys/kernel/debug/tracing/events/power/cpu_frequency/enable: No such file or directory (2)
error opening /sys/kernel/debug/tracing/events/power/cpu_idle/enable: No such file or directory (2)
error opening /sys/kernel/debug/tracing/events/cpufreq_interactive/enable: No such file or directory (2)
error opening /sys/kernel/debug/tracing/buffer_size_kb: No such file or directory (2)
error …Run Code Online (Sandbox Code Playgroud) 是否可以查询两个字段之间的减法结果?
例如,有两个字段:"开始","结束".我想要文件end - start > 10.
这可以直接完成,或者唯一的方法是在加载具有这种差异的文档时创建一个新字段吗?
以下是我目前的结构(不起作用).
父组件:
<template>
<field-input ref="title" :field.sync="title" />
</template>
<script>
import Field from './input/Field'
export default {
components: {
'field-input': Field
},
data() {
return {
title: {
value: '',
warn: false
}
}
}
}
</script>
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子组件:
<template>
<div>
<input type="text" v-model="field.value">
<p v-bind:class="{ 'is-invisible' : !field.warn }">Some text</p>
</div>
</template>
<script>
export default {
props: ['field']
}
</script>
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要求是:
title.warn值在父项中发生更改,class则应更新子项的绑定(field.warn).<input>更新(field.value),title.value则应更新父母的.实现这一目标的最干净的工作解决方案是什么?