OSX v10.6.8和Gnuplot v4.4
我有一个包含8列的数据文件.我想从第6列获取第一个值并将其作为标题.这是我到目前为止所拥有的:
#m1 m2 q taua taue K avgPeriodRatio time
#1 2 3 4 5 6 7 8
K = #read in data here
graph(n) = sprintf("K=%.2e",n)
set term aqua enhanced font "Times-Roman,18"
plot file using 1:3 title graph(K)
以下是我的数据文件的前几行:
1.00e-07 1.00e-07 1.00e+00 1.00e+05 1.00e+04 1.00e+01 1.310 12070.00
1.11e-06 1.00e-07 9.02e-02 1.00e+05 1.00e+04 1.00e+01 1.310 12070.00
2.12e-06 1.00e-07 4.72e-02 1.00e+05 1.00e+04 1.00e+01 1.310 12070.00
3.13e-06 1.00e-07 3.20e-02 1.00e+05 1.00e+04 1.00e+01 1.310 12090.00
我不知道如何正确读取数据,或者这是否是正确的解决方法.
编辑#1
好的,多亏了我现在的mgilson
#m1 m2 q …这是我遇到问题的一段代码的极简化版本.
int i = 0;
int count = 0;
int time = 50;
int steps = 1000;
double Tol = 0.1;
bool crossRes = false;
bool doNext = true;
for (int i=0; i<steps; i++) {
//a lot of operations are done here, I will leave out the details, the only
//important things are that "dif" is calculated each time and doNext either
//stays true or is switched to false
if (doNext = true) {
if (dif <= Tol) count++;
if …