小编Rya*_*ray的帖子

我正在尝试在收到C2DM消息时显示简单的通知.服务提供给UI,但仍然在主线程上运行.我见过有人声称你可以从服务中创建和显示通知.

 @Override
public void onMessage(Context context, Intent intent) {
    Log.w("Messsage","Message Received");
    Bundle extras = intent.getExtras();
    if (extras != null) {
        String payload = (String) extras.get("test");
        createNotification(context,payload);





    }
}

private void createNotification(Context context, String message){
    NotificationManager notificationmanager =  (NotificationManager) context.getSystemService(Context.NOTIFICATION_SERVICE);
    Notification notification = new Notification(R.drawable.default1,message,System.currentTimeMillis());


    notificationmanager.notify(0,notification);
}

}

06-15 15:39:13.580: E/AndroidRuntime(11603): FATAL EXCEPTION: IntentService    [stp.chrome@gmail.com]
06-15 15:39:13.580: E/AndroidRuntime(11603): java.lang.IllegalArgumentException:   contentView required: pkg=com.upmc id=0 notification=Notification(contentView=null vibrate=null,sound=null,defaults=0x0,flags=0x0)
06-15 15:39:13.580: E/AndroidRuntime(11603):    at android.os.Parcel.readException(Parcel.java:1331)
06-15 15:39:13.580: E/AndroidRuntime(11603):    at android.os.Parcel.readException(Parcel.java:1281)
06-15 15:39:13.580: E/AndroidRuntime(11603):    at android.app.INotificationManager$Stub$Proxy.enqueueNotificationWithTag(INotificationManager.java:299)
06-15 …

今天非常简单的问题.当我尝试检索对话框上的按钮的引用时,我总是收到一个空值.

@Override
public void onRestart() {
    super.onRestart();


    //must prompt with modal dialog for pin
    Dialog dialog = new Dialog(this);
    dialog.setOwnerActivity(this);
    dialog.setCancelable(false);

    //check pin
    dialog.setCanceledOnTouchOutside(false);
    //set view to enterpin XML screen
    dialog.setContentView(R.layout.enterpin);
    //register button

    //show dialog
    dialog.show();
    //listen for button being clicked
    Button button = (Button) findViewById(R.id.pinlogin);
    button.setOnClickListener(new OnClickListener(){
        @Override
        public void onClick(View v){
            EditText editText = (EditText) findViewById(R.id.enterpin);
            int enteredPin = Integer.parseInt(editText.getText().toString());
            SharedPreferences sharedP = getPreferences(MODE_PRIVATE);
            int temp = sharedP.getInt("pin", 0);
            if(enteredPin==temp){
                pinCheck = true;
            }else{
                pinCheck = false;
            } …

不要立即标记我重复的问题。我的问题有所不同，因为我有一个格式正确的 SQL 查询。

public static final String TABLE_NAME = "log";
public static final String COLUMN_ID = "_id";
public static final String LOG_TEXT = "logtext";
private static final String TABLE_CREATE = "CREATE TABLE " + TABLE_NAME + " (" +
        COLUMN_ID + " integer primary key autoincrement, " +
        LOG_TEXT + " TEXT not null);";

@Override
public void onCreate(SQLiteDatabase db) {
    db.execSQL(TABLE_CREATE);

}

我在这里查询

String[] columns = {LOG_TEXT,COLUMN_ID};
    Cursor cursor = helper.getReadableDatabase().query(TABLE_NAME, columns, null, null, null, null, COLUMN_ID + " desc"); …