小编Išk*_*uda的帖子

如何在Doctrine 2.0中编写这个SQL查询(并获取结果)？

(SELECT 'group' AS type, 
    CONCAT(u.firstname, " ", u.surname) as fullname, 
    g.name AS subject,
    user_id, 
    who_id, 
    group_id AS subject_id,
    created 
  FROM group_notification 
  JOIN users u ON(who_id = u.id) 
  JOIN groups g ON(group_id = g.id)
)

   UNION 

(SELECT 'event' AS type, 
    CONCAT(u.firstname, " ", u.surname) as fullname, 
    e.name AS subject, 
    user_id, 
    who_id, 
    event_id AS subject_id, 
    created 
  FROM event_notification 
  JOIN users u ON(who_id = u.id) 
  JOIN events e ON(event_id = e.id)
)
   ORDER BY created

谁能告诉我我做错了什么？:-)

我有这个简单的查询:

 var sample = from training in _db.Trainings
              where training.InstructorID == 10
              select new { Something = training.Instructor.UserName };

我把它传递给ViewBag.

ViewBag.Sample = sample;

然后我想在我的视图中访问它,如下所示:

@foreach (var item in ViewBag.Sample) {
    @item.Something
}

我得到错误消息'对象'不包含'Something'的定义.如果我放在那里@item,我得到结果{ Something = SomeUserName }

感谢帮助.

有人可以帮我解决这个异常:

测试方法KravmagaTests.Model.Entities.StudentTest.Create_Valid_Student抛出异常:System.NotSupportedException:无法创建类型为"Kravmaga.Models.Account"的常量值.在此上下文中仅支持原始类型(例如Int32,String和Guid').

我运行这个测试方法时得到这个:

[TestMethod]
public void Create_Valid_Student()
{
    Student student = new Student()
    {
        Username = "username",
        Firstname = "firstname",
        Surname = "surname",
        Email = "email@gmail.com",
        Password = "password",
    };
    KravmagaContext context = new KravmagaContext();
    context.AddToAccounts(student);
    context.Save();
    bool exists = context.Accounts.Contains(student); // THIS THROWS EXCEPTION
    Assert.IsTrue(exists);
}

非常感谢.

有人可以帮助我在C++中序列化这个简单的类:

class State {
public:
    int count;
    Point point;
    double angle;
    Point* possible;
    int possibleSize;
    Line line;
    list<Point> route;

    State() {

    }

    ~State() {
        delete[] possible;
    }

};

// --- Structures

// Line structure (ax + by + c = 0)
struct Line {
    int a;
    int b;
    int c;
};

// Point structure
struct Point {
    int x;
    int y;
};

我不能使用任何第三方类或库,我需要将其序列化为字节数组(或字符串).有人可以写怎么样？我只是不知道如何开始.

非常感谢.