标签: uipickerview

我正在为我正在上课的一个程序工作,程序的一部分需要UIPickerView带有图像.我有拾取器启动并运行,但拾取器中行的高度仍然太小,导致图像(100x100)重叠.我正在寻找一种方法来改变它UIPickerView,使图像适合一行,没有重叠.谢谢

有很多这样的问题,但我相信我的案例是独一无二的.

我在内部单击文本框时会弹出一个选择器视图.用户在选择器视图中选择他们的位置,并将其放入文本框中.

打开选择器视图时,滑块位于第一个元素上,但是如果我单击完成按钮以最小化选择器视图,则不会选择任何元素(即,您必须向下滚动并向上选择第一个元素)

我试过了

    [pickerView selectRow:0 inComponent:0 animated:YES];

以及它的各种组合,但它只将滑块放在该元素上,而不是实际选择它.

一些答案说要在viewDidLoad()方法中应用上面的代码,但不幸的是我从Web服务中提取位置数组并且不能这样做.

理想情况下,我想工作 - 用户在文本框中单击,选择器视图正常弹出,如果在此时单击完成按钮,则选择第一个项目.

先感谢您

编辑12-14-2015:这个问题再次在iOS 7,iOS 8,iOS 9上频繁报道....我认为Apple不再需要这种控制了,应该禁止我们使用它而不是让这样的专业窃听器

我使用UIPickerView和从Xib加载的自定义视图.我正在使用这种方法

-(UIView *)pickerView:(UIPickerView *)pickerView viewForRow:(NSInteger)row 
    forComponent:(NSInteger)component reusingView:(UIView *)view

从UIPickerViewDelegate重用我的视图.

使用iOS 6,我的UIPickerview完美运行,我的视图可以重复使用.

从iOS 7开始,reusingView总是为nil,所以我需要为每一行加载NIB(我有250行).我的观点正在做一些处理,所以它可以占用一小部分内存,但x250 =大内存泄漏.

为了确定问题所在,我用UILabel做了一个简单的项目:

-(UIView *)pickerView:(UIPickerView *)pickerView viewForRow:(NSInteger)row forComponent:(NSInteger)component reusingView:(UIView *)view {

    UILabel *label = (UILabel *)view;
    if(view == nil) {
        label = [[UILabel alloc] initWithFrame:CGRectMake(0, 0, pickerView.frame.size.width, 76)];
    }
    else {
        NSLog(@"*******************************************************");
    }
    NSLog(@"Current inndex : %i",row);
    label.text = [NSString stringWithFormat:@"TITRE %i", row];
    return label;
}

使用iOS 6,我的视图可以正确重用:

2013-12-17 14:27:25.395 EssaiReusedViewPicker [261:907]当前的指数:220 2013-12-17 14:27:25.396 EssaiReusedViewPicker [261:907]*******************************************************2013-12-17 14:27: 25.397 EssaiReusedViewPicker [261:907]当前的指数:221 2013-12-17 14:27:25.404 EssaiReusedViewPicker …

我接受NSString为

NSString *value = [valuelist objectAtIndex:valuerow];
NSString *value2 = [valuelist2 objectAtIndex:valuerow2];

来自UIPickerView.我想要

double *cal = value + (value2 * 8) + 3;


NSString *message =[[NSString alloc] initWithFormat:@"%@",cal];

在我对它进行计算之后,我应该能够在消息中获取字符串..请帮助我的程序崩溃

我想在工具栏上单击完成按钮后关闭UIPickerView(滑出视图).我已将UIPickerView链接为UITextField的inputView,并将UIToolbar设置为UIPickerView的inputAccessoryView.但是,我调用resignFirstResponder的函数不会将UIPicker滑出视图.任何帮助表示赞赏,并提前致谢!

import UIKit

class ViewController: UIViewController, UIPickerViewDataSource, UIPickerViewDelegate {
    // Do any additional setup after loading the view, typically from a nib.

    //initialization constants
    let pickerView = UIPickerView()
    let textField = UITextField()
    let pickerData = ["1","2","three"]


    override func viewDidLoad() {
        //pickerview tool bar
        let toolbar = UIToolbar(frame: CGRectMake(0, 0, 320, 44))
        var items = [AnyObject]()
        //making done button
        let doneButton = UIBarButtonItem(title: "Done", style: .Plain, target: self, action: Selector(donePressed()))
        items.append(doneButton)
        toolbar.barStyle = UIBarStyle.Black
        toolbar.setItems(items, animated: true)


        //creating textfields with a …

我试图在Swift PickerView中使用图像.我不知道如何让图像实际出现在组件中.我知道如何使用带有titleForRow函数的字符串来执行此操作,但我不知道如何使用图像执行此操作.到目前为止,这是我的代码:

import UIKit
class ViewController: UIViewController, UIPickerViewDelegate {

    @IBOutlet weak var pickerView: UIPickerView!


    var imageArray: [UIImage] = [UIImage(named: "washington.jpg")!,
        UIImage(named: "berlin.jpg")!, UIImage(named: "beijing.jpg")!,
        UIImage(named: "tokyo.jpg")!]



    override func viewDidLoad() {
        super.viewDidLoad()
        // Do any additional setup after loading the view, typically from a nib.
    }

    override func didReceiveMemoryWarning() {
        super.didReceiveMemoryWarning()
        // Dispose of any resources that can be recreated.
    }


    // returns the number of 'columns' to display.
    func numberOfComponentsInPickerView(pickerView: UIPickerView) -> Int{

        return 1

    }

    // returns the # …

我不知道我的编码有什么问题.我试着按照教程,但同样的错误发生.

错误:

类型'FourthViewController'不符合协议'UIPickerViewDataSource'

这是我的代码:

import UIKit

let characters = ["Jaja Bink", "Luke", "Han Solo", "Princess Leia"];

let weapons = ["LightSaber", "Pistol", "Keris"];

class FourthViewController: UIViewController, UIPickerViewDataSource, UIPickerViewDelegate {

    @IBOutlet weak var doublePicker: UIPickerView!

    override func viewDidLoad() {
        super.viewDidLoad()

        // Do any additional setup after loading the view.
    }

    override func didReceiveMemoryWarning() {
        super.didReceiveMemoryWarning()
        // Dispose of any resources that can be recreated.
    }

    func numberOfComponentsInPickerView(pickerView: UIPickerView) -> Int {
        return 2
    }


    func pickerView(pickerView: UIPickerView,
                    titleForRow row: Int,
                                forComponent component: …

我使用此代码在uiactionsheet中显示uipicker但当我单击关闭按钮时,我想从视图中删除操作表.那么应该删除actionSheet表单视图的代码.

- (BOOL)textFieldShouldBeginEditing:(UITextField *)textField
{
    UIActionSheet *actionSheet = [[UIActionSheet alloc] initWithTitle:nil delegate:nil cancelButtonTitle:nil destructiveButtonTitle:nil otherButtonTitles:nil];

[actionSheet setActionSheetStyle:UIActionSheetStyleBlackTranslucent];

CGRect pickerFrame = CGRectMake(0, 40, 0, 0);

pickerView = [[UIPickerView alloc] initWithFrame:pickerFrame];
pickerView.showsSelectionIndicator = YES;
pickerView.dataSource = self;
pickerView.delegate = self;

[actionSheet addSubview:pickerView];
[pickerView release];

UISegmentedControl *closeButton = [[UISegmentedControl alloc] initWithItems:[NSArray arrayWithObject:@"Close"]];
closeButton.momentary = YES; 
closeButton.frame = CGRectMake(260, 7.0f, 50.0f, 30.0f);
closeButton.segmentedControlStyle = UISegmentedControlStyleBar;
closeButton.tintColor = [UIColor blackColor];
[closeButton addTarget:self action:@selector(dismissActionSheet:) forControlEvents:UIControlEventValueChanged];
[actionSheet addSubview:closeButton];
[closeButton release];

[actionSheet showInView:self.view];//[UIApplication mainWindow]];

[actionSheet setBounds:CGRectMake(0, 0, 320, …

我有一个带UIPickerView的应用程序.我正在使用该方法返回自定义视图

- (UIView *)pickerView:(UIPickerView *)pickerView viewForRow:(NSInteger)row forComponent:(NSInteger)component reusingView:(UIView *)view 

它在iOS 6中显得很好.在iOS 7中,没有那么多 - 下面的屏幕截图.

请注意,在没有焦点的单元格中,第二列和第三列重叠.中心行是正确的.

有什么建议？

我一直在谷歌搜索如何在UIPickerView中获取当前选择的值,但在任何地方都提到使用row:0等等.

我有一个UIPickerView填充了字符串值,如"一个","两个"等.

现在,当我选择一个值让我们说"两个"时,无论如何我可以得到这个文本.

就像在UITextView中一样,它是_textview.text