我的Django网站有一个Photo模型,代表系统中的照片,我用它Django.contrib.comments来允许用户评论这些.这一切都运行正常,但我想扩展我的Tastypie API,以允许我PhotoResource使用URL 访问评论,例如/api/v1/photo/1/comments1是照片的ID.我能够让URL工作正常,但无论我正在做什么样的过滤,我似乎总是返回完整的注释集,而不仅仅是提供的照片集.我在下面列出了我当前代码API的精选内容:
class CommentResource(ModelResource):
user = fields.ForeignKey(UserResource, 'user')
class Meta:
queryset = Comment.objects.all()
filtering = {
'user': ALL_WITH_RELATIONS,
}
class PhotoResource(ModelResource):
user = fields.ForeignKey(UserResource, 'user')
class Meta:
queryset = Photo.objects.all()
filtering = {
'id': 'exact',
'user': ALL_WITH_RELATIONS
}
def prepend_urls(self):
return [url(r"^(?P<resource_name>%s)/(?P<pk>\w[\w/-]*)/comments%s$" % (self._meta.resource_name, trailing_slash()), self.wrap_view('get_comments'), name="api_get_comments"),
]
def get_comments(self, request, **kwargs):
try:
obj = self.cached_obj_get(request=request, **self.remove_api_resource_names(kwargs))
except ObjectDoesNotExist:
return HttpGone()
except MultipleObjectsReturned:
return HttpMultipleChoices("More than one resource is found at this URI.") …我有两个模型:Project和Album.它们通过oneToOneField相互关联.
相册/ models.py:
class Album(models.Model):
title = models.CharField(_('title'), max_length=128)
slug = models.SlugField(_('slug'), unique=True, default='main-gallery')
项目/ models.py
class Project(models.Model):
title = models.CharField(_('title'), max_length=300)
slug = models.SlugField(_('slug'), unique=True)
main_gallery = models.OneToOneField(Album, verbose_name=_('related main album'), related_name='project', unique=True)
@receiver(pre_save, sender=Project)
def create_project(sender, instance=None, **kwargs):
if instance is None:
try:
str(instance.main_gallery)
except Album.DoesNotExist:
main_gallery = Album.objects.create(title=''.join((instance.title, ' - ', 'main gallery')))
如果创建了项目,也将为其创建相册.这很好用.但是当我尝试使用django tastypie在我的api中创建一个时它不会工作:
class AlbumResource(ModelResource):
class Meta:
queryset = Album.objects.all()
resource_name = 'album'
#fields = ['title','slug',]
def dehydrate_resource_uri(self, bundle):
return bundle.data['slug']
class ProjectResource(ModelResource):
main_gallery = …如果我尝试过滤相关对象中的字段,则Tastypie会返回错误.例如,跑步
curl -H "Accept: application/json" \
"http://localhost:8080/wordgame/api/v1/rounds/?format=json&players__username=moe"
返回"在'玩家'字段中,查询不允许超过一个级别." 从本质上讲,我正在努力做我目前在Django shell中所做的事情:
Round.objects.all().filter(players__username=moe.username)
我使用以下代码,为简洁起见,我简化了以下代码:
# wordgame/api.py which has tastypie resources
class RoundResource(ModelResource):
players = fields.ManyToManyField(UserResource, 'players',full=True)
. . .
class Meta:
queryset = Round.objects.all()
resource_name = 'rounds'
filtering = {
'players': ALL,
}
class UserResource(ModelResource):
class Meta:
queryset = User.objects.all()
resource_name = 'players'
filtering = {
'username': ALL,
}
# wordgame/models.py which has Django models
class Round(models.Model):
players = models.ManyToManyField(User)
word = models.CharField(max_length=75)
. . .
我假设因为UserResource在字段'username'上定义了一个过滤器,它应该可以工作,但事实并非如此.我甚至尝试将"players__username"添加到RoundResource中的过滤器,但是这也不起作用.
我有2个型号如下
商人
class MerchantProfile(StateModel):
class Meta:
verbose_name = "Merchant Profile"
ordering = ('name',)
def __unicode__(self):
return u'%s' % (self.name,)
user = models.OneToOneField(UserProfile, related_name="merchant_profile")
payment_card = models.OneToOneField(PaymentCard, related_name="merchant_profile")
current_state = models.IntegerField('State', choices=STATE_CHOICES)
name = models.CharField('Merchant Name', max_length=64)
类别
class Category(models.Model):
merchant = models.ForeignKey(MerchantProfile, related_name="category")
name = models.CharField(max_length=30)
is_active=models.BooleanField()
我有资源文件如下
儿童资源
class MerchantCategoryResource(ModelResource):
api_key = fields.CharField(attribute='merchant__user__api_key', readonly=True)
class Meta:
#get username from headers and apply filter query
queryset = Category.objects.all()
resource_name = 'merchantcategory'
#excludes = ['id','email', 'password', 'is_active', 'is_staff', 'is_superuser']
detail_allowed_methods = …从客户端javascript发送到我们的服务器时,我们最近经历了一个非常奇怪但非常一致的延迟.
这是我们的技术堆栈,从前到后:
http://上游)unix://上游插座)(旁注:您是否曾对网络开发的复杂程度感到敬畏？)
这是事件的时间表:
.save()新创建的Backbone APIModel..sync()风向client.send()调度新创建的对象的方式$.ajax().Location标题指向新资源.xhr触发成功处理程序$.Deferred()对象解析,触发任何相关的客户端代码成功处理程序.其他需要考虑的细节:
console.time()确定延迟在65,000ms范围内变化.我正在做的未经证实的假设:
请原谅详细的细节,但我已尽力消除变量,目前,我觉得这个问题是以下之一:
我希望#3.有任何想法吗？
我正在为一个项目开发一个API,我通过OrderProducts建立了一个关系Order/Products,如下所示:
在models.py中
class Product(models.Model):
...
class Order(models.Model):
products = models.ManyToManyField(Product, verbose_name='Products', through='OrderProducts')
...
class OrderProducts(models.Model):
order = models.ForeignKey(Order)
product = models.ForeignKey(Product)
...
现在,当我通过API加载订单时,我也希望获得相关产品,所以我尝试了这个(使用django-tastypie):
按顺序/ api.py
class OrderResource(ModelResource):
products = fields.ToManyField('order.api.ProductResource', products, full=True)
class Meta:
queryset = Order.objects.all()
resource_name = 'order'
一切都适用于列出订单资源.我获得了嵌入了产品数据的订单资源.
问题是我无法使用api创建或编辑Order对象.由于我在ManytoMany关系中使用直通模型,因此ManyToManyField(产品)没有.add()方法.但是tastypie试图在发布/向其发送数据时在OrderResource的产品字段上调用.add().
{"error_message": "'ManyRelatedManager' object has no attribute 'add'", "traceback": "Traceback (most recent call last):\n\n File \"/Library/Python/2.7/site-packages/tastypie/resources.py\", line 192, in wrapper\n response = callback(request, *args, **kwargs)\n\n File \"/Library/Python/2.7/site-packages/tastypie/resources.py\", line 397, in dispatch_list\n return self.dispatch('list', request, **kwargs)\n\n File \"/Library/Python/2.7/site-packages/tastypie/resources.py\", line 427, …我需要列出每个员工的工作时间,但我得到:
模型''具有空属性'work_journey',并且不允许空值.
上:
/休息/ tastypie /雇员/？格式= JSON
models.py
class Employee():
registration = models.CharField(u'Registration', max_length=20, unique=True)
work_journey = models.ForeignKey(WorkJourney, null=True, blank=True)
hr.models.py
class WorkJourney(ModelPlus):
code = models.CharField(max_length=10, null=True, unique=True)
workinghours = models.CharField(max_length=40)
excluded = models.BooleanField()
class Meta:
db_table='work_journey'
verbose_name = u'Work Journey'
def __unicode__(self):
return self.workinghours
resources.py
from suap.models import Employee
from hr.models import WorkJourney
class WorkJourneyResource(ModelResource):
class Meta:
queryset = WorkJourney.objects.all()
resource_name = 'work_journey'
authentication = BasicAuthentication()
class EmployeeResource(ModelResource):
journey = fields.ForeignKey(WorkJourney, 'work_journey')
class Meta:
queryset = Employee.objects.all()
resource_name = …我们正在使用iphone应用程序构建Django后端,并且还希望允许通过Web /移动浏览器登录.要求是能够从网站/移动浏览器以及通过iPhone应用程序注册和登录.我还集成了django-registration进行注册,登录,注销等.
什么是首选方法,以便通过iPhone应用程序和移动浏览器进行注册,登录,注销？
讨论最多的方法似乎如下:
在我们的案例中,安全性和仅查看用户相关数据的能力非常重要,因为数据非常敏感.
任何建议都非常感谢,肯定也会帮助其他人.
提前致谢.新
我在开发带有tastypie的api时遇到了问题.我想要的主要是知道是否有办法直接将图像发布到json内的tastypie.
在我的模型中,我现在正在使用ImageField:
class MyClass(models.Model):
description = models.TextField()
user = models.ForeignKey(User)
photo = models.ImageField(upload_to="image", null=True, blank=True)
然后在我的api文件中:
class InquiryResource(ModelResource):
user = fields.ForeignKey(UserResource, 'user' ,full=True)
photo = fields.FileField(attribute = 'photo', null=True, blank = True)
class Meta :
queryset = MyClass.objects.all()
resource_name = "MyClass"
authorization = Authorization()
当我发送一个只有用户和描述的基本json时,它运行良好.然后当我去添加关于我的图像的信息时:
{ ... ,
photo : {
Content-Type : "image/png",
file : "base64string", <----- this one contains the file as a long string
name : "test.png"
} ...}
我收到一条错误消息:'dict'对象没有属性'_commited'
使用tastypie本地上传文件是否有"干净的方式",还是应该使用Base64FileField？
谢谢
我需要在django中使用tastypie修补用户个人资料图片.我使用Django 1.6,AngularJs,它使用Django的普通Authentication()和DjangoAuthorization()类.
当我尝试使用'CONTENT-TYPE:Multipart/form-data'上传图像时.我收到以下错误.
error_message: "You cannot access body after reading from request's data stream"
首先我知道Tastypie没有官方支持多部分表单数据.我希望有一个猴子补丁或任何有效的东西,直到tastypie支持Multipart-Form Data.
我已经对上面做了一些研究,我已经研究了一些问题:
参考文献:
虽然上面的方法看起来像是一个黑客..我想在我的资源中尝试一下.
我的资源如下:
class UserProfileResource(ModelResource):
user = fields.ToOneField(UserResource, 'user', full=True)
profile_img = fields.FileField(attribute="img", null=True, blank=True)
"""docstring for ProfileResource"""
def alter_list_data_to_serialize(self, request, data):
if request.GET.get('meta_only'):
return {'meta': data['meta']}
return data
def authorized_read_list(self, object_list, bundle):
return object_list.filter(user=bundle.request.user).select_related()
def obj_create(self, bundle, **kwargs):
return super(UserProfileResource, self).obj_create(bundle, user=bundle.request.user)
def dehydrate(self, bundle):
bundle.data['groups'] = [g.name for g in bundle.request.user.groups.all()]
return bundle
"""Deserialize for multipart Data"""
def deserialize(self, …tastypie ×10
django ×9
python ×5
javascript ×2
backbone.js ×1
file-upload ×1
nginx ×1
orm ×1
rest ×1