让我们std::unique_lock从标准库中实现:
struct defer_lock_t { explicit defer_lock_t() = default; };
struct try_to_lock_t { explicit try_to_lock_t() = default; };
struct adopt_lock_t { explicit adopt_lock_t() = default; };
inline constexpr defer_lock_t defer_lock {};
inline constexpr try_to_lock_t try_to_lock {};
inline constexpr adopt_lock_t adopt_lock {};
unique_lock (mutex_type& m, defer_lock_t t) noexcept;
unique_lock (mutex_type& m, try_to_lock_t t);
unique_lock (mutex_type& m, adopt_lock_t t);
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是否有人不会/不能/不应该使用枚举而不是结构来实现标签调度?如:
enum defer_lock_t { defer_lock };
enum try_to_lock_t { try_to_lock };
enum adopt_lock_t { adopt_lock };
unique_lock (mutex_type& m, defer_lock_t t) noexcept; …Run Code Online (Sandbox Code Playgroud) 在此视频中,https: //youtu.be/Vkck4EU2lOU?t = 582展示了“标签分发”和SFINAE作为替代方案,使您可以选择所需的模板功能。
这是对的吗?不是使用SFINAE进行“标签分配”吗?如果正确,那么SFINAE和代码分发之间到底有什么区别?
下面的代码会val2在两次f()调用中打印。f()根据枚举值执行特定分支的正确方法是什么?
enum class E
{
val1,
val2
};
using val1_t = std::integral_constant<E, E::val1>;
using val2_t = std::integral_constant<E, E::val2>;
template <typename T>
void f(T t)
{
if constexpr (std::is_same_v<T, val1_t>)
{
std::cerr << "val1\n";
}
else
{
std::cerr << "val2\n";
}
}
int main()
{
f(E::val1);
f(E::val2);
}
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