标签: syntax-error

假设我有一个看起来像这样的函数:

def _thread_function(arg1, arg2=None, arg3=None):
    #Random code

现在我想使用该函数创建一个线程,并给它arg2而不是arg3.我正在尝试如下:

#Note: in this code block I have already set a variable called arg1 and a variable called arg2
threading.Thread(target=self._thread_function, args=(arg1, arg2=arg2), name="thread_function").start()

上面的代码给了我一个语法错误.我如何修复它以便我可以将参数作为arg2传递给线程？

仅在结帐时和单个产品页面上,我在控制台日志中收到以下错误:

VM35594:1 Uncaught SyntaxError: Unexpected token u in JSON at position 0
    at JSON.parse (<anonymous>)
    at run (layout.min.js:9)
    at app.min.js:1
    at main.min.js:2
    at Object.execCb (require.min.js:112)
    at Module.check (require.min.js:56)
    at Module.<anonymous> (require.min.js:72)
    at require.min.js:11
    at require.min.js:74
    at each (require.min.js:3)

我正在使用单页结帐扩展程序,但是当我禁用时,错误仍然显示.我认为它可能与产品页面上的评论有关(因为我将评论移出选项卡),但撤消该更改并未修复产品页面上的错误.

我一直试图修复,无法找到错误不断出现的原因.Pmin,Pmax,w,fi1和fi2都被赋予了有限值

guess=Pmin+(Pmax-Pmin)*((1-w**2)*fi1+(w**2)*fi2)

当我从代码中删除此行时,在下一行代码中出现相同的错误,再次无缘无故我能想到

编辑:这是我所指的代码块:

def Psat(self, T):
    pop= self.getPborder(T)
    boolean=int(pop[0])

    P1=pop[1]
    P2=pop[2]
    if boolean:
        Pmin = float(min([P1, P2]))
        Pmax = float(max([P1, P2]))
        Tr=T/self.typeMolecule.Tc
        w=0.5*(1+scipy.tanh((10**5)*(Tr-0.6)))
        fi1=0.5*(1-scipy.tanh(8*((Tr**0.4)-1)))
        fi2=0.460*scipy.sqrt(1-(Tr-0.566)**2/(0.434**2)+0.494

        guess = Pmin+(Pmax-Pmin)*((1-w**2)*fi1+(w**2)*fi2)   #error here

        solution = scipy.optimize.newton(funcPsat,guess, args=(T,self))

我开始使用a ContextThemeWrapper来动态地应用一个样式ImageButton; 基于对我的另一个问题的回答,以及对其他类似 问题的回答.

ContextThemeWrapper wrapper = new ContextThemeWrapper(getContext(), mStyleRes);
mImageButton = new AppCompatImageButton(wrapper, null, 0);

但最近一个lint错误开始出现在ContextThemeWrapper构造函数上:

ContextThemeWrapper 只能从同一个库组中调用(groupId = com.android.support)

我注意到标有@RestrictTo(LIBRARY_GROUP)注释的类,这会导致lint错误出现.但是我找不到任何关于它为什么仅限于com.android.support图书馆组的信息.

据我所知,这是以View编程方式应用样式,主题或主题叠加的唯一方法; 除了将默认样式属性设置为构造函数中的第三个参数之外.所以我想知道为什么它的使用会受到限制; 在支持库之外使用类有什么问题吗？可能会有我不知道的副作用吗？

我遇到的唯一类似的问题是关于(现在已修复)的错误; 导致此lint错误显示在onCreate子类的方法上AppCompatActivity.我认为这不是一个错误,而是一个故意的限制; 我想知道背后的推理.

我应该注意; 这个限制(截至目前)实际上似乎对使用a的代码没有影响ContextThemeWrapper.它编译并运行良好,并按照我的预期工作.

我使用$ .ajax()从POST请求收到此响应:

{"command": 6,"log_size":50,"log":[
    {"type": 30,"tag": "*NETEVENT*","sensors": "0D","ti": 1047161877,"to": 0},
    {"type": 30,"tag": " __START__","sensors": "00","ti": 0000011410,"to": 0},
    {"type": 30,"tag": "*NETEVENT*","sensors": "0A","ti": 0000011411,"to": 0},
    {"type": 30,"tag": "*NETEVENT*","sensors": "0B","ti": 0000011411,"to": 0},
    {"type": 30,"tag": "*NETEVENT*","sensors": "0D","ti": 0000011412,"to": 0},
    {"type": 30,"tag": " __START__","sensors": "00","ti": 1047215799,"to": 0},
    {"type": 30,"tag": "*NETEVENT*","sensors": "0A","ti": 1047215799,"to": 0},
    {"type": 30,"tag": " __START__","sensors": "00","ti": 1047218051,"to": 0},
    {"type": 30,"tag": "*NETEVENT*","sensors": "0D","ti": 0000002598,"to": 0},
    {"type": 30,"tag": "*NETEVENT*","sensors": "0B","ti": 1047068795,"to": 0},
    {"type": 30,"tag": "*NETEVENT*","sensors": "0D","ti": 1047068796,"to": 0},
    {"type": 30,"tag": "*NETEVENT*","sensors": "0A","ti": 1047071223,"to": 0},
    {"type": …

我试图从以下数据获取数据:

http://api.convoytrucking.net/api.php?api_key=public&show=player&player_name=Mick_Gibson

但如果我想用这段代码获取player_name变量:

<?  
$js = file_get_contents('http://api.convoytrucking.net/api.php?api_key=public&show=player&player_name=Mick_Gibson');
  $pjs = json_decode($js);
  var_dump($pjs->{'player_name'});
?>

我收到错误:

注意:尝试在第9行+ var_dump()的**\htdocs\index.php中获取非对象的属性返回:NULL

var_dump($pjs) 收益:

array(1) { [0]=> object(stdClass)#52 (15) { ["player_name"]=> string(11) "Mick_Gibson" ["player_id"]=> int(88) ["rank"]=> string(12) "FIRE TURTLEE" ["lastseen"]=> int(1393797692) ["registration_date"]=> string(19) "2012-08-10 17:01:34" ["last_mission_date"]=> string(19) "2014-03-02 21:41:50" ["time_offset"]=> int(1) ["house_id"]=> int(611) ["fines"]=> int(0) ["wanted"]=> int(0) ["police_badge"]=> bool(true) ["vip"]=> bool(false) ["staff"]=> NULL ["stats"]=> object(stdClass)#53 (23) { ["score"]=> int(2941) ["convoy_score"]=> int(818) ["ARTIC"]=> int(515) ["DUMPER"]=> int(565) ["TANKER"]=> int(56) ["CEMENT"]=> int(163) ["TRASH"]=> int(7) ["ARMORED"]=> int(9) ["VAN"]=> int(501) ["TOW"]=> int(502) …

我认为T?只是编译器的简写Nullable<T>.根据MSDN:

语法T?是简写Nullable<T>,其中T是值类型.这两种形式是可以互换的.

但是,有一点(微不足道)的差异:Visual Studio不允许我在shorthands上调用静态方法:

bool b1 = Nullable<int>.Equals(1, 2); //no error
bool b2 = int?.Equals(1, 2); //syntax error "Invalid expression term 'int'"

为什么？这种限制有什么理由吗？

根据The Well Grounded Rubyist:

Ruby允许在哈希键位置使用特殊形式的符号表示,在符号之后使用冒号而不是之前的冒号,并删除哈希分隔符箭头.换句话说,这个:

hash = { :name => "David", :age => 49 }

也可以这样写:

hash = { name: David, age: 49 }

我在ruby 1.8.7和1.9.2中尝试了前面的代码 - 它无法正常工作.我究竟做错了什么？

我试图重载c ++运算符==但我得到一些错误...

错误C2662:'CombatEvent :: getType':无法将'this'指针从'const CombatEvent'转换为'CombatEvent&'

这个错误就在这一行

if (lhs.getType() == rhs.getType())

看下面的代码:

class CombatEvent {

public:
    CombatEvent(void);
    ~CombatEvent(void);

    enum CombatEventType {
        AttackingType,
        ...
        LowResourcesType
    };

    CombatEventType getType();
    BaseAgent* getAgent();

    friend bool operator<(const CombatEvent& lhs, const CombatEvent& rhs) {

        if (lhs.getType() == rhs.getType())
            return true;

        return false;
    }

    friend bool operator==(const CombatEvent& lhs, const CombatEvent& rhs) {

        if (lhs.getType() == rhs.getType())
            return true;

        return false;
    }

private: 
    UnitType unitType;
}

任何人都可以帮忙吗？

我正在使用IntelliJ IDEA(2016.3)linux version进行Java开发.如下图所示当鼠标指针悬停在错误行上时,错误消息重叠,javadoc使得更难以读取给定的错误消息.如何解决这个问题？提前致谢