我知道Python中不需要分号,但它们可以用于将多个语句塞入一行,例如
>>> x = 42; y = 54
我一直认为分号相当于换行符.所以我有点惊讶(在推特上没有Ned Batchelder)双分号是一个SyntaxError:
>>> x = 42
>>> x = 42;
>>> x = 42;;
File "<stdin>", line 1
x = 42;;
^
SyntaxError: invalid syntax
我假设最后一个程序相当于x = 42\n\n.我以为分号之间的陈述被视为一个空行,一个无操作.显然不是.
为什么这是一个错误？
我正在关注Django教程https://docs.djangoproject.com/es/1.10/intro/tutorial01/
我已经创建了一个"mysite"虚拟项目(我的第一个)并尝试在不改变它的情况下测试它.
django-admin startproject mysite
cd mysite
python manage.py runserver
File "manage.py", line 14
) from exc
^
SyntaxError: invalid syntax
我在由系统本身生成的文件上获得了一个SyntaxError.我似乎找不到其他人经历过同样的问题.
我将添加一些我的设置数据,以防它可能有用
$ vpython --version
Python 2.7.12
$ pip --version
pip 9.0.1 from /home/frank/.local/lib/python2.7/site-packages (python 2.7)
$ python -m django --version
1.10.6
有人能帮帮我吗？
更新:添加autogenerated manage.py的内容
cat manage.py
#!/usr/bin/env python3
import os
import sys
if __name__ == "__main__":
os.environ.setdefault("DJANGO_SETTINGS_MODULE", "mysite.settings")
try:
from django.core.management import execute_from_command_line
except ImportError as exc:
raise ImportError(
"Couldn't import Django. Are you sure it's installed …我正在尝试通过Laravel连接PostgreSQL数据库,以便进行php工匠迁移,但似乎没有被定向,因为它正在读取MySQL的数据库名称.
以下是来自database.php的命令:
'connections' => array(
'sqlite' => array(
'driver' => 'sqlite',
'database' => __DIR__.'/../database/production.sqlite',
'prefix' => '',
),
'mysql' => array(
'driver' => 'mysql',
'host' => 'localhost',
'database' => 'database',
'username' => 'root',
'password' => '',
'charset' => 'utf8',
'collation' => 'utf8_unicode_ci',
'prefix' => '',
),
'pgsql' => array(
'driver' => 'pgsql',
'host' => 'localhost',
'database' => 'postgres',
'username' => 'postgres',
'password' => 'root',
'charset' => 'utf8',
'prefix' => '',
'schema' => 'public',
),
'sqlsrv' => array(
'driver' => 'sqlsrv', …Ruby:
true == true == true
语法错误,意外的tEQ
与JavaScript:
true == true == true
// => true
与C:
1 == 1 == 1
// => 1
ruby operators syntax-error operator-precedence associativity
我收到这个PHP错误:
PHP Notice: Undefined offset: 1
这是抛出它的PHP代码:
$file_handle = fopen($path."/Summary/data.txt","r"); //open text file
$data = array(); // create new array map
while (!feof($file_handle) ) {
$line_of_text = fgets($file_handle); // read in each line
$parts = array_map('trim', explode(':', $line_of_text, 2));
// separates line_of_text by ':' trim strings for extra space
$data[$parts[0]] = $parts[1];
// map the resulting parts into array
//$results('NAME_BEFORE_:') = VALUE_AFTER_:
}
这个错误是什么意思？是什么导致这个错误？
向MySQL发出命令时,我收到错误#1064"语法错误".
这是什么意思？
我该如何解决？
我有一个HTML文件:
<!DOCTYPE HTML>
<html lang="en-US" ng-app="Todo">
<head>
<meta charset="UTF-8">
<title>DemoAPI</title>
<meta name="viewport">
<link rel="stylesheet" href="http://maxcdn.bootstrapcdn.com/bootstrap/3.2.0/css/bootstrap.min.css">
<script src="http://ajax.googleapis.com/ajax/libs/angularjs/1.3.14/angular.min.js"></script>
<script type="text/javascript" src="https://cdnjs.cloudflare.com/ajax/libs/jquery/2.1.4/jquery.js"></script>
<link rel="stylesheet" href="./Client/css/styling.css" />
<script type="text/javascript" src="core.js"></script>
</head>
错误说:
Uncaught SyntaxError: Unexpected token < core.js: 1
它显示了在错误<!doctype html>的app.html.
core.js 看起来像这样:
angular.module('Todo', [])
.controller('mainController', function($scope, $http)
{
$scope.formData = {};
// get all and show them
$http.get('/musicians')
.success(function(data) {
$scope.todos = data;
console.log(data);
})
.error(function(data) {
console.log('Error: ' + data);
});
//get with an id
$scope.getOneTodo = …运行此代码时,我收到一个非常奇怪的JavaScript错误:
<script type = 'text/javascript'>
var ask = confirm('".$message."');
if (ask == false)
{
return false;
}
else
{
return true;
}
</script>
在JavaScript控制台中,它说:
Syntax Error: Illegal return statement
它发生在return true;和return false;
(我从php函数回应这个javascript; $message变量是php参数之一)
我的代码出了什么问题？
这是我写这行时的错误self.MessageTextField.delegate = self:
/ChatApp/ViewController.swift:27:42:无法将类型'ViewController'的值赋给'UITextFieldDelegate？'类型的值
这是我的Swift代码(ViewerController.swift):
//
// ViewController.swift
// ChatApp
//
// Created by David Chen on 15/4/12.
// Copyright (c) 2015? cwsoft. All rights reserved.
//
import UIKit
import Parse
class ViewController: UIViewController, UITableViewDelegate, UITableViewDataSource {
var messagesArray:[String] = [String]()
@IBOutlet weak var MessageTableView: UITableView!
@IBOutlet weak var ButtonSend: UIButton!
@IBOutlet weak var DockViewHeightConstraint: NSLayoutConstraint!
@IBOutlet weak var MessageTextField: UITextField!
override func viewDidLoad() {
super.viewDidLoad()
//
self.MessageTableView.delegate = self
self.MessageTableView.dataSource = self
//Set delegate
self.MessageTextField.delegate = self …为什么Python print在第9行的简单语句中给出了语法错误？
import hashlib, sys
m = hashlib.md5()
hash = ""
hash_file = raw_input("What is the file name in which the hash resides? ")
wordlist = raw_input("What is your wordlist? (Enter the file name) ")
try:
hashdocument = open(hash_file,"r")
except IOError:
print "Invalid file." # Syntax error: invalid syntax
raw_input()
sys.exit()
else:
hash = hashdocument.readline()
hash = hash.replace("\n","")
Python的版本是:
Python 3.2.2 (default, Sep 4 2011, 09:07:29) [MSC v.1500 64 bit (AMD64)] on win
32
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