我正在使用Spring Framework 4.0.7,以及MVC和Rest
我可以和平地工作:
@Controller ResponseEntity<T>例如:
@Controller
@RequestMapping("/person")
@Profile("responseentity")
public class PersonRestResponseEntityController {
用这个方法(只是为了创建)
@RequestMapping(value="/", method=RequestMethod.POST)
public ResponseEntity<Void> createPerson(@RequestBody Person person, UriComponentsBuilder ucb){
logger.info("PersonRestResponseEntityController - createPerson");
if(person==null)
logger.error("person is null!!!");
else
logger.info("{}", person.toString());
personMapRepository.savePerson(person);
HttpHeaders headers = new HttpHeaders();
headers.add("1", "uno");
//http://localhost:8080/spring-utility/person/1
headers.setLocation(ucb.path("/person/{id}").buildAndExpand(person.getId()).toUri());
return new ResponseEntity<>(headers, HttpStatus.CREATED);
}
返回一些东西
@RequestMapping(value="/{id}", method=RequestMethod.GET)
public ResponseEntity<Person> getPerson(@PathVariable Integer id){
logger.info("PersonRestResponseEntityController - getPerson - id: {}", id);
Person person = personMapRepository.findPerson(id);
return new ResponseEntity<>(person, HttpStatus.FOUND);
}
工作良好
我可以这样做:
@RestController(我知道它与@Controller+ …@GetMapping和之间有什么区别@RequestMapping(method = RequestMethod.GET)？
我在一些Spring Reactive示例中看到过,
@GetMapping而不是使用它@RequestMapping
Spring版本4.2.0,Hibernate 4.1.4
这是我的Controller功能:
@RequestMapping(value = "/mobile/getcomp", method = RequestMethod.GET)
@ResponseBody
public List<Company> listforCompanies() {
List<Company> listOfCompanies= new ArrayList<Company>();
listOfCompanies = companyManager.getAllCompanies();
return listOfCompanies;
}
杰克逊JSON映射器依赖Pom.xml:
<!-- Jackson JSON Mapper -->
<dependency>
<groupId>org.codehaus.jackson</groupId>
<artifactId>jackson-mapper-asl</artifactId>
<version>${jackson.version}</version>
</dependency>
获取列表ArrayList,但返回时会显示以下错误:
SEVERE: Servlet.service() for servlet [dispatcherServlet] in context with path [/IrApp] threw exception [Request processing failed; nested exception is java.lang.IllegalArgumentException: No converter found for return value of type: class java.util.ArrayList] with root cause
java.lang.IllegalArgumentException: No converter found for return …我正在尝试使用@ControllerAdvice处理MethodArgumentNotValidException作为下面给出的代码:
@ControllerAdvice
public class RestResponseEntityExceptionHandler extends ResponseEntityExceptionHandler {
private Logger log = LoggerFactory.getLogger(RestResponseEntityExceptionHandler.class);
@Autowired
private ApplicationContext applicationContext;
@ExceptionHandler({ ConstraintViolationException.class })
@ResponseStatus(HttpStatus.BAD_REQUEST)
@ResponseBody
public ErrorWrapper handleConstraintViolationException(ConstraintViolationException e) {
String fieldName = e.getConstraintName();
String message = getResourceMessage(fieldName + ".alreadyExists", "Already Exists");
return new ErrorWrapper(fieldName + ".error", message);
}
@ExceptionHandler({ MethodArgumentNotValidException.class })
@ResponseStatus(HttpStatus.BAD_REQUEST)
@ResponseBody
public ErrorWrapper handleMethodArgumentNotValidException(MethodArgumentNotValidException e) {
return new ErrorWrapper(".error", "test");
}
private String getResourceMessage(String key, String defaultMessage) {
String message = applicationContext.getMessage(key, null, Locale.getDefault());
if (StringUtils.isNotEmpty(message)) {
return message;
} …我试图了解这里的区别.我看到一个类已经使用相同的包示例注释了它们:
@Configuration
@EntityScan("some.known.persistence")
@ComponentScan({ "some.known.persistence"})
public class ApiConfig {
}
我理解与API文档的不同之处,但希望详细了解.这也意味着扫描的任何东西@ComponentScan都具有更广泛的可见性和Spring背景,而@EntityScan不是.如果这样使用某些属性@ComponentScan应该已经足够需要在JPA上下文中绑定,不是吗？
我正在使用Spring 4.0.7
我通过JavaConfig对配置Spring MVC进行了研究.
实际上直到昨天我已经看到使用这两个选项的两种配置
注意:(2)是两个类,一个用于扩展,另一个用于实现
我正在使用(2)因为我找到了很多例子,我可以配置转换器,格式化程序,资源处理程序等...
但是在最近的几天里,我试图帮助StackOverflow上的一个问题,我确实认识到(1)存在..我在Google上做了一些关于(1)的概述,并且存在一些与(1)一起工作的例子
我的问题是这篇文章的标题如何描述.
谢谢
我在Tomcat 6.0.37中部署Spring 4.0.1应用程序时遇到异常:
SEVERE: Exception sending context initialized event to listener instance of class org.springframework.web.context.ContextLoaderListener
org.springframework.beans.factory.BeanCreationException: Error creating bean with name 'org.springframework.validation.beanvalidation.OptionalValidatorFactoryBean#0': Invocation of init method failed; nested exception is java.lang.AbstractMethodError: org.hibernate.validator.internal.engine.ConfigurationImpl.getDefaultParameterNameProvider()Ljavax/validation/ParameterNameProvider;
at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.initializeBean(AbstractAutowireCapableBeanFactory.java:1553)
at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.doCreateBean(AbstractAutowireCapableBeanFactory.java:539)
at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.createBean(AbstractAutowireCapableBeanFactory.java:475)
at org.springframework.beans.factory.support.AbstractBeanFactory$1.getObject(AbstractBeanFactory.java:304)
at org.springframework.beans.factory.support.DefaultSingletonBeanRegistry.getSingleton(DefaultSingletonBeanRegistry.java:228)
at org.springframework.beans.factory.support.AbstractBeanFactory.doGetBean(AbstractBeanFactory.java:300)
at org.springframework.beans.factory.support.AbstractBeanFactory.getBean(AbstractBeanFactory.java:195)
at org.springframework.beans.factory.support.DefaultListableBeanFactory.preInstantiateSingletons(DefaultListableBeanFactory.java:700)
at org.springframework.context.support.AbstractApplicationContext.finishBeanFactoryInitialization(AbstractApplicationContext.java:760)
at org.springframework.context.support.AbstractApplicationContext.refresh(AbstractApplicationContext.java:482)
at org.springframework.web.context.ContextLoader.configureAndRefreshWebApplicationContext(ContextLoader.java:403)
at org.springframework.web.context.ContextLoader.initWebApplicationContext(ContextLoader.java:306)
at org.springframework.web.context.ContextLoaderListener.contextInitialized(ContextLoaderListener.java:106)
at org.apache.catalina.core.StandardContext.listenerStart(StandardContext.java:4206)
at org.apache.catalina.core.StandardContext.start(StandardContext.java:4705)
at org.apache.catalina.core.ContainerBase.addChildInternal(ContainerBase.java:799)
at org.apache.catalina.core.ContainerBase.addChild(ContainerBase.java:779)
at org.apache.catalina.core.StandardHost.addChild(StandardHost.java:601)
at org.apache.catalina.startup.HostConfig.deployWAR(HostConfig.java:943)
at org.apache.catalina.startup.HostConfig.deployWARs(HostConfig.java:778)
at org.apache.catalina.startup.HostConfig.deployApps(HostConfig.java:504)
at org.apache.catalina.startup.HostConfig.start(HostConfig.java:1317)
at org.apache.catalina.startup.HostConfig.lifecycleEvent(HostConfig.java:324)
at org.apache.catalina.util.LifecycleSupport.fireLifecycleEvent(LifecycleSupport.java:142) …我一直在调查使用JasperReports(6.0.0)和Spring MVC(4.1.3)来生成PDF报告.Spring充斥着"Spring特定"方式与JasperReports集成以生成PDF:
JasperReportsPdfView JasperReportsMultiFormatView JasperReportsViewResolver 我努力在网上找到好的,完整的例子,并想分享我的发现(见下面的答案).
随意添加与"如何将JasperReports与Spring4集成"相关的其他方法和/或改进？
我正在使用Spring 4.0.7
关于Spring MVC,出于研究目的,我有以下内容:
@RequestMapping(value="/getjsonperson",
method=RequestMethod.GET,
produces=MediaType.APPLICATION_JSON_VALUE)
public @ResponseBody Person getJSONPerson(){
logger.info("getJSONPerson - getjsonperson");
return PersonFactory.createPerson();
}
@RequestMapping(value="/getperson.json", method=RequestMethod.GET)
public @ResponseBody Person getPersonJSON(){
logger.info("getPerson - getpersonJSON");
return PersonFactory.createPerson();
}
每个都工作正常,观察JSON,有和没有扩展:
对于XML也是如此
@RequestMapping(value="/getxmlperson",
method=RequestMethod.GET,
produces=MediaType.APPLICATION_XML_VALUE
)
public @ResponseBody Person getXMLPerson(){
logger.info("getXMLPerson - getxmlperson");
return PersonFactory.createPerson();
}
@RequestMapping(value="/getperson.xml", method=RequestMethod.GET)
@ResponseBody
public Person getPersonXML(){
logger.info("getPerson - getpersonXML");
return PersonFactory.createPerson();
}
每个都工作正常,观察XML,有和没有扩展:
现在关于Restful我有以下内容:
@RequestMapping(value="/person/{id}/",
method=RequestMethod.GET,
produces={MediaType.APPLICATION_JSON_VALUE,
MediaType.APPLICATION_XML_VALUE})
public ResponseEntity<Person> getPersonCustomizedRestrict(@PathVariable Integer id){
Person person = personMapRepository.findPerson(id); …有没有办法将WebSockets与SockJS客户端和Spring 4服务器一起使用但不使用STOMP？
基于Spring网站的这个教程,我知道如何使用Stomp和Spring 4设置基于WebSocket的应用程序.在客户端,我们有:
var socket = new SockJS('/hello');
stompClient = Stomp.over(socket);
stompClient.connect({}, function(frame) {
setConnected(true);
console.log('Connected: ' + frame);
stompClient.subscribe('/topic/greetings', function(greeting){
showGreeting(JSON.parse(greeting.body).content);
});
});
在服务器端,我们在控制器中有以下内容:
@MessageMapping("/hello")
@SendTo("/topic/greetings")
public Greeting greeting(HelloMessage message) throws Exception {
Thread.sleep(3000); // simulated delay
return new Greeting("Hello, " + message.getName() + "!");
}
现在,据我所知,@MessageMapping("/hello")确保如果将消息发送到目标"/hello",则将greeting()调用该方法.并且由于stompClient订阅了"/topic/greetings",所以@SendTo("/topic/greetings")会将消息发送回stompClient.
但是上面的问题是stompClient是一个Stomp对象.我想简单地使用sock.send('test');并将其发送到我的服务器目的地.我想做@SendTo("myownclientdestinationmap"),我可以收到它
sock.onmessage = function(e) {
console.log('message', e.data);
};
那么,使用Spring 4,SockJS和没有Stomp的任何方法都可以做到这一点？或者Spring 4 WebSocket只支持Stomp？